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natima [27]
3 years ago
6

Kaushik had three pendulum bobs made of steel of the same length but different masses of 10 g, 50 g and 100 g respectively. When

he performed an experiment with them to find the time period, which of these statements would he consider to be correct? a. The time period is maximum with 10 g bob. b. The time period is maximum with 50 g bob. c. Time period remains the same in all. d. None of these is true.
Physics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

c. Time period remains the same in all.

Explanation:

In order to answer this question, we need to analyze the parameters, upon which the time period of a pendulum depends. We know that the time of a pendulum is given by the following formula:

T = 2π√(L/g)

where,

T = Time period

L = Length of pendulum

g = acceleration due to gravity

The formula clearly shows that the time period of the pendulum depends only upon the length of pendulum and value of g. And the time period of a pendulum does not depend upon the mass of the bob. Hence, the time period for each of the three pendulums will remain same. So, the correct option will be:

<u>c. Time period remains the same in all.</u>

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In 'coin on card' experiment a smooth card is used. ​
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Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

5 0
3 years ago
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A parallel circuit contains an 18-V battery wired with 2 bulbs with resistances of 8
RSB [31]

Answer:

See below

Explanation:

Total current will be   18 v/ 8 ohms +   18v / 24 ohms = 3 amps

Equivalent resistance   =   1 / (1/8 + 1/24) = 6 Ω

7 0
2 years ago
Which subatomic particle has the smallest mass?
spin [16.1K]

Answer:

quark

Explanation:

neutrón= 1.675 x 10-27 kg

proton=1,673 x 10-27 kg

electron=9,11 x 10-31 kg

quark=7,13 - 14,26 · 10−30 kg

3 0
2 years ago
a 0.199 kg snowball moving west makes an inelastic collision with a 2.89 kg box moving 0.523 m/s west. afterward,they move west
kogti [31]

Answer:

The initial velocity of the snowball was 22.21 m/s

Explanation:

Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.

Let m_1 be the mass of the ball, and v_1 be its initial velocity; let m_2 be the mass of the box, and v_2 be its velocity; let v_f be the final velocity after the collision, then according to the law of conservation of momentum:

m_1v_1+m_2v_2=v_f(m_1+m_2).

From this we solve for v_1, the initial velocity of the snowball:

\boxed{v_1=\frac{v_f(m_1+m_2)-m_2v_2}{m_1}}

now we plug in the numerical values m_1=0.199\:kg, m_2=2.89\:kg, v_2=0.523\:m/s, and v_f=1.92\:m/s to get:

v_1=\frac{1.92*(0.199+2.89)-2.89*0.523}{0.199}

\boxed{v_1=22.21\:m/s}

The initial velocity of the snowball is 22.21 m/s.

<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>

4 0
3 years ago
A bulldozer does 4,500 J of work to push a mound of soil to the top of a ramp that is 15 m high. The ramp is at an angle of 35°
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<em>Answer</em>


Force = 170 N



<em>Explanation</em>

First find the distance (d) travelled by the bulldozer.


Sin 35 = 15/d

d = 15/(sin 35)

= 26.15m


Now;

work done = force × distance.


4500 J = force × 26.15


dividing both sides by 26.15,


Force = 4500/26.15

= 172.07 N


Answer to two significant figures = 170 N

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3 years ago
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