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torisob [31]
3 years ago
7

2cm

Mathematics
1 answer:
harkovskaia [24]2 years ago
7 0

Answer:

C

Step-by-step explanation:

Retangular prisms volume= lengthxwidthxheight

therefor you have to include all three number making you answer C

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Solve the simultaneous equations 5x+4y = 1 and 3x - 6 y = 2.
hjlf

x=31​,y=−61​

Put the equations in standard form and then use matrices to solve the system of equations.

5x+4y=1,3x−6y=2

Write the equations in matrix form.

(53​4−6​)(xy​)=(12​)

Left multiply the equation by the inverse matrix of (53​4−6​).

inverse((53​4−6​))(53​4−6​)(xy​)=inverse((53​4−6​))(12​)

The product of a matrix and its inverse is the identity matrix.

(10​01​)(xy​)=inverse((53​4−6​))(12​)

Multiply the matrices on the left hand side of the equal sign.

(xy​)=inverse((53​4−6​))(12​)

For the 2×2 matrix (ac​bd​), the inverse matrix is (ad−bcd​ad−bc−c​​ad−bc−b​ad−bca​​), so the matrix equation can be rewritten as a matrix multiplication problem.

(xy​)=(5(−6)−4×3−6​−5(−6)−4×33​​−5(−6)−4×34​5(−6)−4×35​​)(12​)

Do the arithmetic.

(xy​)=(71​141​​212​−425​​)(12​)

Multiply the matrices.

(xy​)=(71​+212​×2141​−425​×2​)

Do the arithmetic.

(xy​)=(31​−61​​)

Extract the matrix elements x and y.

x=31​,y=−61​

5 0
3 years ago
Read 2 more answers
Please help, i’m not sure if i’m correct
hammer [34]

Answer:

Looks good to me! :)

Step-by-step explanation: Hope you have a great rest of your day!

7 0
3 years ago
If f(x)=3x5−10x3+5, on what intervals is f″(x)>0?
Ksivusya [100]

Answer:

(0.7937,\infty)

Step-by-step explanation:

we are given an algebraic function in x, such that

f(x) = 3x^5-10x^3+5

To find when second derivative >0

For this let us find first and second derivative by successive differentiation.

f(x) = 3x^5-10x^3+5\\f'(x) =15x^4-30x^2\\f'(x)=60x^3-30

when ii derivative >0 we have

60x^3-30>0

x^3>0.5\\x>0.7937

f"(x)>0 in

(0.7937,\infty)

5 0
2 years ago
Recursive definitions for subsets of binary strings.Give a recursive definition for the specified subset of the binary strings.
dmitriy555 [2]

Answer:

Step-by-step explanation:

A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your

b2n+32n+3 = 2 (2n+2)22 b2n+12n+1

your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:

1. Either placing a 1 in available n places (because you can't place it at the end)

2. or by placing a zero in available n+1 places.

0 ϵ P

x ϵ P → 1x ϵ P , x1 ϵ P

x' ϵ P,x'' ϵ P → xx'x''ϵ P

3 0
3 years ago
The number of marbles of different colors stored in a hat is listed below:
Kamila [148]
There is a 1/4 chance of getting the Blue Marble out of the bag. But when it is 2 in a row you have to multiply your chances so it would be 1/4 * 1/4 or 1/16
7 0
3 years ago
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