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4 years ago

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A wire is stretched right to its breaking point by a 5000 N force. A longer wire made of the same material has the same diameter

. Is the force that will stretch it right to its breaking point larger than, smaller than, or equal to 5000 N? Explain.

1 answer:

leva [86]4 years ago

4 0

Answer:

Equal to 5000N

Explanation:

The stress on the material is defined by force per unit of cross-sectional area. So it depends on the force and the diameter of the wire, which is the same for both wires. The material that defines the breaking point, is also the same. Therefore, both wires have their breaking point the same at 5000N. The wire length plays no role in here.

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3 years ago

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Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

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Explanation:

Given:

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$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

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$t=\frac{d}{v_x}$

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$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

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<u>Time taken to reach this height:</u>

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

<u>We observe that </u> $t>t'$ <u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

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skad [1K]

Mass of the diver (m) = 90 Kg.
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<u>Answers:</u>

<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>

<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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