The momentum of the truck is given by:
p = mv
p = momentum, m = mass, v = velocity
There isn't too much work to do here; the truck is at rest, therefore its velocity is 0. This means the product of m and v is 0, giving the momentum as 0.
Answer:
Required diameter of hose pipe = 0.2864 mm
Solution:
From the continuity eqn, the fluid flow rate is given by:
Av = 
where
A = cross-sectional area = 
r = hose pipe radius
v = velocity of gas
Also, 
Using:
1 gallon = 3.854 l
1 mile = 1609.34 m

Therefore,






The diameter of the hose pipe = 2r = 
The diameter of the hose pipe = 
Answer:
Explanation:
a )
Frequency n = 450 x 10⁶ .
20 light years = 20 x 9.461 x 10¹⁵m
Let power of source be P
Intensity at distance R = 
Substituting the given values
8.5 x 10⁻¹⁰ = 
P = 3822457 x 10²⁰ W.
b )
Half the power will be from electric and half will be from magnetic field.
Total power = 8.5 x 10⁻¹⁰ W
Half = 4.25 x 10⁻¹⁰ W .
power of electric field
= 
ε is permittivity , E₀ is amplitude of electric field , c is velocity of light .
Putting the values
4.25 x 10⁻¹⁰ = .5 x 8.85 x 10⁻¹² x E² x 3 x 10⁸
E₀² = .32 x 10⁻⁶
E₀ = .565 x 10⁻³ W / s .
Answer:
first negative and then positve
Answer:
a) v=2.743m/s
b) 
c) T=2.543N
Explanation:
First, calculate the height of the ball at the starting point:


At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

Solving for v:

if h is the height loss: (l-y')
v=2.743m/s
The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):


To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:
