Answer:
Supersaturated.
Explanation:
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In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.
However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.
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The atomic number(Z) is equal to the number of protons to equal to number of electrons.
The number of neutrons is equal to atomic mass minus the atomic number
n=A-Z
For Zn^2+, Z=28, e=28
For iron, Z=25,A=55
The number of neutrons is 55-25=30
The charge is zero
For O^2-, Z=8+2=10, n=p=10
The number of neutrons is 16-10=6
For sulfur, Z=16,A=34
For S2-, Z=16+2=18, A=34
The charge is 2-
- The atomic number is the basis of the periodic table.
- It is equal to the number of protons.
- The number of neutrons is atomic mass minus atomic number.
To learn more about atomic number visit:
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According to the law of conservation of mass, the amount of BARIUM present of the reactants is the same as the amount present in the products (the precipitate).
(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt
(10.0 g) / (0.0480 mol) = 208.3 g/mol
So it must have been BaCl2, because the molar mass of Barium is 137 which leave 71 grams left. Since Barium is a +2 charge, it means the atom next to it must be twice. Chlorine mass is 35, which twice is 71
