Erosion from the waves wash away the top layer making it flat on top.
Answer:
a
No
b
100 mm Hg
Explanation:
From the question we are told that
The vapor pressure of CHCl3, is 
The temperature of CHCl3 is 
The volume of the container is 
The temperature of the container is 
The mass of CHCl3 is m = 0.380 g
Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

Here M is the molar mass of CHCl3 with the value 
=> 
=>
Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

Here R is the gas constant with value 
So
Given that the number of moles of CHCl3 evaporated is less than the number of moles of CHCl3 initially present , then it mean s that not all the liquid evaporated
At equilibrium the temperature of CHCl3 will be equal to the pressure of air so the pressure at equilibrium is 100 mmHg
Answer:
<h3>The answer is 40.96%</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula

From the question
actual density = 2.49g/mL
error = 2.49 - 1.47 = 1.02
We have

We have the final answer as
<h3>40.96 %</h3>
Hope this helps you
Answer:
Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.
Explanation:
Glycogen is the form that glucose is stored in human body.
Cellulose is the structural part of plant cell walls and human cannot digest it.
Amylose is the polysaccharide linked mainly by the the bonds of
1,4 glycosidic.
Cellulose is an unbranched polysaccharide linked mainly by the bonds of
1,4 glycosidic.
Amylopetin and Glycogen are branched polysaccharides linked by the bonds of
1,4 glycosidic and
1,6 glycosidic.
Amylopetin and Cellulose are mainly stored in plants.
Answer:
10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.
Explanation:
Hello!
In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.
Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.
Best regards!