Question

A helium balloon has a volume of 2.00L at 101kpa. As the balloon rises the pressure drops to 97.0kPa. What is the new volume?

Answer 1

Answer:

2.1L

                 

Explanation:

Given parameters:

Initial volume  = 2L

Initial pressure  = 101kPa

Final pressure  = 97kPa

Unknown:

Final or new volume  = ?

Solution:

Now to solve his problem which relates pressure and volume, we simply apply Boyle's law which is mathematically expressed below;

          P₁ V₁  = P₂ V₂

P and V are pressure and volume

1 and 2 are initial and final states;$\frac{101 x 2}{97}$

         101 x 2  = 97 x V₂

              V₂  =  $\frac{101 x 2}{97}$

               V₂ = 2.1L

                 

Answer 2

Answer:

2.08L

Explanation:

V1 = 2.00L

P1 = 101kPa

P2 = 97.0kPa

V2 = ?

from Boyle's law,

P1V1 = P2V2

101 × 2 = 97 × V2

V2 = 202/97 = 2.08L

Therefore, the new volume is 2.08L