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2 years ago

A helium balloon has a volume of 2.00L at 101kpa. As the balloon rises the pressure drops to 97.0kPa. What is the new volume?

Chemistry

2 answers:

Valentin [98]2 years ago

5 0

Answer:

2.1L

Explanation:

Given parameters:

Initial volume = 2L

Initial pressure = 101kPa

Final pressure = 97kPa

Unknown:

Final or new volume = ?

Solution:

Now to solve his problem which relates pressure and volume, we simply apply Boyle's law which is mathematically expressed below;

P₁ V₁ = P₂ V₂

P and V are pressure and volume

1 and 2 are initial and final states; $\frac{101 x 2}{97}$

101 x 2 = 97 x V₂

V₂ = $\frac{101 x 2}{97}$

V₂ = 2.1L

Mrrafil [7]2 years ago

4 0

Answer:

2.08L

Explanation:

V1 = 2.00L

P1 = 101kPa

P2 = 97.0kPa

V2 = ?

from Boyle's law,

P1V1 = P2V2

101 × 2 = 97 × V2

V2 = 202/97 = 2.08L

Therefore, the new volume is 2.08L

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A piece of copper alloy with a mass of 85.0 g is heated from 30. °C to 45 °C. In the process, it absorbs 523 J of energy as heat

Ne4ueva [31]

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

$c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].$

6 0

2 years ago

You just got home from a run on a hot Atlanta afternoon. You grab a 1.00 liter bottle of water and drink three quarters of it in

-Dominant- [34]

Answer:

¾ litters of water was consumed

2.24 litters = 1 mole of water

Therefore ¾÷2.24 moles was consumed

0.33 moles

8 0

3 years ago

Which of the following elements would form the smallest ionic radius and why?

AnnyKZ [126]

Answer:

Sodium

Explanation:

5 0

2 years ago

When 1.98g of a hydrocarbon is burned in a bomb calorimeter, the temperature increases by 2.06∘C. If the heat capacity of the ca

schepotkina [342]

Answer:

8.3 kJ

Explanation:

In this problem we have to consider that both water and the calorimeter absorb the heat of combustion, so we will calculate them:

q for water:

q H₂O = m x c x ΔT where m: mass of water = 944 mL x 1 g/mL = 944 g

c: specific heat of water = 4.186 J/gºC

ΔT : change in temperature = 2.06 ºC

so solving for q :

q H₂O = 944 g x 4.186 J/gºC x 2.06 ºC = 8,140 J

For calorimeter

q calorimeter = C x ΔT where C: heat capacity of calorimeter = 69.6 ºC

ΔT : change in temperature = 2.06 ºC

q calorimeter = 69.60J x 2.06 ºC = 143.4 J

Total heat released = 8,140 J + 143.4 J = 8,2836 J

Converting into kilojoules by dividing by 1000 we will have answered the question:

8,2836 J x 1 kJ/J = 8.3 kJ

7 0

3 years ago

1. NaOH mass of a solution of 200g in which its percentage is 25%. What mass of sulfuric acid solution is needed to completely n

Ede4ka [16]

Answer:

$m_{H2SO4$ = 61.25 g

$m_{Na2SO4}$ = 88.75 g

Explanation:

$m_{NaOH}$ = $\frac{200 . 25 }{100}$ = 50 g

⇒ $n_{NaOH}$ = $\frac{50}{40}$ = 1.25 (moles)

2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O

2 : 1 : 1 : 2

1.25 (moles)

⇒ $n_{H2SO4}$ = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ $m_{H2SO4}$ = 0.625 × 98 = 61.25 g

$n_{Na2SO4}$ = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ $m_{Na2SO4}$ = 0.625 × 142 = 88.75 g

4 0

3 years ago