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QveST [7]
2 years ago
14

A helium balloon has a volume of 2.00L at 101kpa. As the balloon rises the pressure drops to 97.0kPa. What is the new volume?

Chemistry
2 answers:
Valentin [98]2 years ago
5 0

Answer:

2.1L

                 

Explanation:

Given parameters:

Initial volume  = 2L

Initial pressure  = 101kPa

Final pressure  = 97kPa

Unknown:

Final or new volume  = ?

Solution:

Now to solve his problem which relates pressure and volume, we simply apply Boyle's law which is mathematically expressed below;

          P₁ V₁  = P₂ V₂

P and V are pressure and volume

1 and 2 are initial and final states;\frac{101 x 2}{97}

         101 x 2  = 97 x V₂

              V₂  =  \frac{101 x 2}{97}

               V₂ = 2.1L

                 

Mrrafil [7]2 years ago
4 0

Answer:

2.08L

Explanation:

V1 = 2.00L

P1 = 101kPa

P2 = 97.0kPa

V2 = ?

from Boyle's law,

P1V1 = P2V2

101 × 2 = 97 × V2

V2 = 202/97 = 2.08L

Therefore, the new volume is 2.08L

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NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container. 
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Carbon dioxide gas is produced by the reaction of oxygen gas and solid carbon . Write a balanced chemical equation for this reac
grandymaker [24]

I think it’s like this.

C+2O→CO2

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What is the main factor that prevents the growth of tropical plants in the northern part of the us
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Extreme weather e.g. snow and cold weather. Another main contributing factor is that many places have a long dry season.
3 0
3 years ago
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
2 years ago
a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?
viva [34]

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

Temperature = 9°C

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

                16 g of O₂ -------------------- 1 mol

                0.29 g of O₂ ----------------   x

                    x = (0.29 x 1)/16

                    x = 0.29/16

                    x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

              PV = nRT

-Solve for P

              P = nRT/V

-Substitution

              P = (0.018 x 0.082 x 282) / 2.3

-Simplification

              P = 0.416/2.3

-Result

               P = 0.18 atm

5 0
3 years ago
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