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3 years ago

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PLEASE HELP! Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an

angle of 63.0° with the
horizontal. What is the height of the building?
A. 174 m
B. 110 m
C. 98 m
D. 50 m

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

The height of building should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.

Explanation:

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i is the current

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Therefore, the current is the rate of change of the charge passing through a given point over time.

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$Q = i t$

This equation is valid if the current is constant: if the current is not constant, then the total charge is simply equal to the area under a current vs time graph.

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$A_2 = (0.002 s - 0.001 s)(0.010 A)=1\cdot 10^{-5}C$

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