Answer:
A. The project's energy costs will decrease
Explanation:
Since the project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow for on-site renewable energy.
Hence, the project's energy costs will decrease very well because it's implementing both of these strategies;
- Area with demand-response program.
- On-site renewable energy.
<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent.
vi = 0
vf = x
d = ?
d = vi + 1/2 a t^2
d = 0 + 1/2 (9.8) (1.8)^2
d = 15.9 m (counting sig figs)</span>
Ke=34J. The canoe's kinetic energy floating downriver at a speed of 2m/s and 17kg mass is 34J.
This is a problem of kinetic energy, which is a form of energy, known as motion energy. The kinetic energy of an object is that which is produced because of its movements that depends on its mass and velocity.
The kinetic energy is represented by the following formula: Ke = ½ mv². The kinetic energy is measured in Joules (J), the mass in kilograms (kg) and the speed in meters over seconds (m/s).
A small 17kg canoe is floating downriver at a speed of 2m/s. Let's calculate canoe's kinetic energy.
Ke= (17kg)[(2m/s)²]/2= 68/2 kg m²/s²=34J
.
Answer:
Electric potential energy at the negative terminal: 
Explanation:
When a particle with charge 
travels across a potential difference 
, then its change in electric potential energy is
In this problem, we know that:
The particle is an electron, so its charge is
We also know that the positive terminal is at potential
While the negative terminal is at potential
Therefore, the potential difference (final minus initial) is
So, the change in potential energy of the electron is
This means that the electron when it is at the negative terminal has of energy more than when it is at the positive terminal.
Since the potential at the positive terminal is 0, this means that the electric potential energy of the electron at the negative end is
Answer:
Parietal on the first blank and temporal on the second
