The correct answer is D. 1.13 x 10^22 atoms are present in 0.378 g of neon. Avogadro's number (6.022 x 10^23) gives the ratio of representative particles per mole of substance. For every mole of substance, there are 6.022 x 10^23 representative particles present. Since 0.378 g of neon is less than one mole of neon, the answer should be less than Avogadro's number, which makes option D a logical answer.
Further Explanation:
To get the number of atoms present in 0.378 g of neon the following steps must be done:
- Convert the mass of neon into moles.
- Use Avogadro's number to get the number of atoms present in the given moles of neon.
STEP 1: Convert 0.378 g of Neon to moles of Neon
STEP 2: Use Avogadro's number to calculate the number of atoms of Ne
Since the given, 0.378 g has 3 significant figures, the final answer must also have 3 significant figures. Therefore,
A. 6.02 x 10^23 atoms is FALSE because the given amount of neon is less than one mole. Hence, the number of atoms cannot be equal to Avogadro's number.
B. 1.187 x 10^-2 atoms is FALSE because atoms are very very small particles. It will require a large number of atoms to make up something that is measurable like a 0.378 g sample of neon. Having less than 1 atom to make up this much sample is not logical.
C. 2.28 x 10^23 atoms is FALSE because this much atoms make up 0.3781 mol of Neon but the given is 0.378 <u>grams</u> not moles of Ne.
D. 1.13 x 10^22 atoms is TRUE because the value is less than 6.022 x 10^23 which is logical since the sample is less than 1 mole.
Learn More
- Learn more about Avogadro's Number brainly.com/question/12972204
- Learn more about mole conversion brainly.com/question/12979299?source=aid8145232
- Learn more about Inert Gases brainly.com/question/7581131?source=aid8145177
Keywords: Avogadro's Number, Mole Conversion, Atoms