what conversion factors should be used to convert 18 mi/hr to ft/sec? what conversion factors should be used to convert 18 mi/hr
1 answer:
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The force of gravity on the object is 14.47 N
Explanation:
The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by
where
m is the mass of the object
g is the acceleration of gravity at the location of the object
IN this problem, we have:
m = 24.52 kg (mass of the object)
(acceleration of gravity on Pluto)
Substituting, we find the force of gravity on the object:
Learn more about forces and weight:
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Answer:
Part A:
Part B:
Explanation:
Part A:
Formula of Electric Field Strength:
Where:
x is the distance from the ring
R is the radius of the ring
is constant permittivity of free space=8.854*10^-12 farads/meter
Q is the charge
For right Ring E at the midpoint can be calculated as:
x for right plate=25/2=12.5 cm=0.125 m
Radius=R=10/2=5 cm=0.05 m
For Left Ring E at the midpoint can be calculated as:
Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.
Electric Field at midpoint:
Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.
Part B:
At center of left ring:
Due to left ring Electric field at center is zero because x=0.
Due to right ring Electric field at center of left ring:
Now: x=25 cm= o.25 m (To the center of left ring)
Electric Field Strength at center of left ring is same as that of right ring.