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kolbaska11 [484]
3 years ago
6

what conversion factors should be used to convert 18 mi/hr to ft/sec? what conversion factors should be used to convert 18 mi/hr

to ft/sec?
Physics
1 answer:
trasher [3.6K]3 years ago
7 0
The conversion that should be made for this certain problem would be from miles to feet and from hours to second. The conversion of miles to feet would have a factor of 5280. For hours to second the factor would be 3600. Hope this answers the question.
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The signal to a speaker causes .5 amps of current. The signal level is increased to 2.5 amps. What is the gain, rounded to the n
devlian [24]

Explanation:

It is given that,

The signal to a speaker causes 0.5 amps of current, I_1=0.5\ A

The signal level is increased to 2.5 amps, I_2=2.5\ A

We need to find the gain to the nearest decibel. The decibel gain formula of the speaker is given by :

db=20\ log(\dfrac{I_2}{I_1})

db=20\ log(\dfrac{2.5}{0.5})

db = 13.97 db

or

db = 14 db

So, the gain pf the speaker is 14 db. Hence, this is the required solution.

7 0
3 years ago
A car travels along a straight road at a steady 40 MPH.Are the forces on the car balanced or unbalanced? Explain.
Nutka1998 [239]
They are balanced b/c the motion is constant
8 0
3 years ago
as you go above earths surface, the acceleration due to gravity will decrease. find the height, i meters, above the earths surfa
aleksklad [387]

Answer:

1.23×10⁸ m

Explanation:

Acceleration due to gravity is:

a = GM / r²

where G is the universal gravitational constant,

M is the mass of the planet,

and r is the distance from the center of the planet to the object.

When the object is on the surface of the Earth, a = g and r = R.

g = GM / R²

When the object is at height i above the surface, a = 1/410 g and r = i + R.

1/410 g = GM / (i + R)²

Divide the first equation by the second:

g / (1/410 g) = (GM / R²) / (GM / (i + R)²)

410 = (i + R)² / R²

410 R² = (i + R)²

410 R² = i² + 2iR + R²

0 = i² + 2iR − 409R²

Solve with quadratic formula:

i = [ -2R ± √((2R)² − 4(1)(-409R²)) ] / 2(1)

i = [ -2R ± √(1640R²) ] / 2

i = (-2R ± 2R√410) / 2

i = -R ± R√410

i = (-1 ± √410) R

Since i > 0:

i = (-1 + √410) R

R = 6.37×10⁶ m:

i ≈ 1.23×10⁸ m

8 0
3 years ago
Suppose an oven's radiation wavelength is 0.125 m. a container with 350.00 g of water was placed in the oven, and the temperatur
ivann1987 [24]
The heat (energy) needed to raise the temperature of the water is given by
Q=m C_S (T_f - T_i)=(350.0 g)(4.18 J/gC)(80C-20C)=87780 J

The wavelength of the radiation of the oven is \lambda=0.125 m, so the energy of a single photon of this radiation is
E=h \frac{c}{\lambda}=(6.6 \cdot 10^{-34}J) \frac{3\cdot 10^8 m/s}{0.125 m}=1.6 \cdot 10^{-24} J

So, the number of photons required to heat the water is the total energy absorbed by the water divided by the energy of a single photon:
N= \frac{Q}{E}= \frac{87780 J}{1.6\cdot 10^{-24}J}=  5.5 \cdot 10^{28} photons
8 0
3 years ago
A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 4kg. The carriage ha
Ira Lisetskai [31]

Answer:

E=252J

Explanation:

The total mechanical energy of an object or system is given by:

E mech=K+U

Where K is the kinetic energy of the object and U is the potential energy of the object. The carriage, sitting motionless at the top of the hill, has only potential energy in the form of gravitational potential energy.

Gravitational potential energy is given by:

Ug=mgh

Where m is the mass of the object, g is the gravitational acceleration constant, and h is the height of the object above some specific reference point, in this case the ground 21 m below.

The weight of a stationary object at the surface of the earth is equal to the force of gravity acting on the object.

W=→Fg=mg

We are given that the carriage weighs 12 N, therefore mg=12N.

Ug=12N⋅21m

⇒Ug=252Nm=252J

Hope it helped, God bless you!

5 0
3 years ago
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