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2 years ago

How many PO43? ions are in a mole of K3PO4?

Chemistry

1 answer:

adoni [48]2 years ago

7 0

K₃PO₄ → 3K⁺ (aq) + PO₄³⁻(aq)

One mole of PO₄³⁻ ion gets dissociated from one mole of K₃PO₄

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ ions

One mole of PO₄³⁻ ions x (6.022 x 10²³ ions/ 1 mole of PO₄³⁻ ions )

= 6.022 x 10²³ ions

Therefore , there are 6.022 x 10²³ PO₄³⁻ ions in a mole of K₃PO₄.

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3 years ago

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3 years ago

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Answer : The formula for the compound sodium carbonate is $Na_2CO_3$

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Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) $CO_3^{2-}$ .

Here, sodium is having an oxidation state of +1 called as $Na^{1+}$ cation and carbonate $CO_3^{2-}$ is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, $Na_2CO_3$

Hence, the formula for the compound sodium carbonate is $Na_2CO_3$

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In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) $MnO_4^{1-}$ .

Here, potassium is having an oxidation state of +1 called as $K^{1+}$ cation and permanganate $MnO_4^{1-}$ is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, $KMnO_4$

Hence, the formula for the compound potassium permanganate is $KMnO_4$

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3 years ago