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Olin [163]
3 years ago
11

A black lift of amber is placed in water and a laser beam travels from the water through the amber. The angle of incidence is 35

degrees while the angle of refraction is 24 degrees. What is the index of refraction of amber
Physics
1 answer:
horsena [70]3 years ago
6 0

Answer:

Explanation:

refractive index of ember = sin of angle of incidence / sin of angle of refraction

= sin 35 / sin24

= .5735 / .4067

= 1.41

This is refractive index of ember with respect to water

refractive index of ember with respect to water

= wμe = μe / μw

μe = wμe x  μw

= 1.33 x 1.41

= 1.87

refractive index of ember with respect to air = 1.87 .

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A stationary police car emits a sound of frequency 1240 HzHz that bounces off of a car on the highway and returns with a frequen
lara [203]

Answer:

frequency =  1475.45 Hz

Explanation:

given data

frequency f1 = 1215 Hz,

frequency f2 = 1265 Hz

police car moving vp = 25.0 m/s

solution

speed of sound u = 343 m / s

speed of the other car = v

when the police car is stationary

the frequency the other car receives is

f2 =  f1  ×  \dfrac{u+v}{u}      ................1

and

the frequency the police car receives is

 f2 =  f1  ×  \dfrac{u}{u-v}      ..................2

now from equation 1 and 2

\frac{f2}{f1} = \dfrac{u+v}{u-v}

 \frac{1275}{1240} = \frac{u+v}{u-v}

v =\frac{1275-1240}{1275+1240}\times 343  

v = 4.77 m/s

and

frequency the other car receives is  

f2 = f1 ×   \dfrac{u+v}{u-vp}       ......................3

and

the frequency the police car receives is

f2 = f1 ×  \dfrac{u+vp}{u - v}       .......................4

now we get

f2 = f1 ×  \dfrac{(u+v)(u + vp)}{(u-v)(u-vp)}      

f2 =    1240\times \frac{(343+4.77)(343+25)}{(343-4.77)(343-25)}        

f2 =  1475.45 Hz

 

4 0
3 years ago
What is the gravitational force between mars and Phobos
alina1380 [7]

Answer:

F=5.16\times 10^{15}\ N

Explanation:

We have,

Mass of Mars is, m_M=6.42\times 10^{23}\ kg

Mass of its moon Phobos, m_P=1.06\times 10^{16}\ kg

Distance between Mars and Phobos, d = 9378 km

It is required to find the gravitational force between Mars and Phobos. The force between two masses is given by

F=G\dfrac{m_Mm_P}{d^2}

Plugging all values, we get :

F=6.67\times 10^{-11}\times \dfrac{6.42\times 10^{23}\times 1.06\times 10^{16}}{(9378\times 10^3)^2}\\\\F=5.16\times 10^{15}\ N

So, the gravitational force is 5.16\times 10^{15}\ N.

8 0
3 years ago
How do you know the earth is rotating on its axis
cupoosta [38]

Answer:

Read below!

Explanation:

You can watch the sun wheel across the sky during the day, and the stars at night. Focus a telescope on any star besides the north star--especially southern stars--and you can watch them drift across your field of view.  

An alternative explanation is that all the stars are painted on (or holes in) some canopy that rotates around the earth. This explanation does not account for the motion of the "wanderers," or planets, as the Greeks called them, or for the path of the moon among the stars.  

As we know the stars are massive bodies of significant and varying distance to the earth, the notion they all swing around us in unison seems highly implausible

4 0
3 years ago
Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now _____ .
Arte-miy333 [17]
<span>Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now based on gravity and friction alone.</span>
6 0
3 years ago
Read 2 more answers
On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east.
Talja [164]

This is a vector subraction problem.

5 0
3 years ago
Read 2 more answers
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