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Olin [163]
3 years ago
11

A black lift of amber is placed in water and a laser beam travels from the water through the amber. The angle of incidence is 35

degrees while the angle of refraction is 24 degrees. What is the index of refraction of amber
Physics
1 answer:
horsena [70]3 years ago
6 0

Answer:

Explanation:

refractive index of ember = sin of angle of incidence / sin of angle of refraction

= sin 35 / sin24

= .5735 / .4067

= 1.41

This is refractive index of ember with respect to water

refractive index of ember with respect to water

= wμe = μe / μw

μe = wμe x  μw

= 1.33 x 1.41

= 1.87

refractive index of ember with respect to air = 1.87 .

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Suppose your surface body temperature averaged 90 degrees F. How much radiant energy in W/m^2 would be emitted from your body?
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493 \; \text{W}\cdot \text{m}^{-2}.

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\dfrac{P}{A} = \sigma \cdot T^{4} = 5.67 \times 10^{-8} \times 305.372^{4} = 493\; \text{W}\cdot \text{m}^{-2}.

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