Answer:
Presence or absence of cilia/stinging cells.
Numbers.
Retractability.
Number of cells.
Explanation:
Apart from size difference, tentacles in Cnidaria and Bryozoa differs such that:
- <em>The tentacles in Cnidaria have no cilia surrounding them while those of Bryozoa are ciliated. Instead of cilia, the tentacles in Cnidaria have stinging cells.</em>
- <em>Tentacles in Cnidaria are fixed in number while the number may vary in Bryozoa.</em>
- <em>Tentacles in Cnidaria are often retractable while retractability is not possible in Bryozoa.</em>
- <em>Cnidaria tentacles are made up of multiple cells while those of Bryozoa are made up of single cells.</em>
Answer:
Phenotype- 100% for the recessive trait (aa, bb)
Explanation:
This happens because of the mode of inheritance, which would mask the dominant trait, during a cross. Therefore, this would lead to all offspring not expressing the dominant phenotype
Answer:
look at the pictures
Explanation:
1. If we cross the parental generation which is RR x rr, the probability of the F1 generation to get rough coat is 100% and they will be a carrier of the recessive trait smooth coat.
Since the phenotypic ratio is 100% heterozygous Rr, in crossing the F1 to get the F2, we will use the genotype Rr. To get the F2, use the cross Rr x Rr.
The phenotypic ration for F2 is 3:1. There is 75% to get rough coat and 25% smooth. The answer is based on the result on the Punnett square. On the other hand, the genotypic ratio is 1:2:1. There is 25% probability to get RR genotype, 50% Rr, and 25% rr.
2. Since the two parental mice got 6 albino offspring and 5 brown mice offspring, it is approximately 50%. it takes a parental mice who is Brown that is carrying an albino trait crossed with an albino to get offspring with almost the same number. Therefore, the genotype of the brown mice is Aa.