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2 years ago

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An object accelerates downward at a constant rate of 3.75 m/s2 while completely submerged in water. Neglect the viscosity (fluid

friction) of the water. The average density of the object is ______ kg/m3. The density of water is 1000 kg/m3 and g

1 answer:

guajiro [1.7K]2 years ago

7 0

Answer:

Do = density of obect Dw = density of water

Weight of object = V g Do

Weight of water = V g Dw

F = m a = V Do a = V g Do - V g Dw

Acceleration of object = mass * force on object

Do (g - a) = Dw g

Do = Dw ( 1 / (1 - a / g) = 1000 * 1 / (1 - 3.75 / 9.80) kg/m^3

Do = 1441 kg / m^3

If no acceleration then density of object = density of water

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