Answer:
Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.
Explanation:
Answer:
The time taken by the airplane to take off, t = 11.46 s
Explanation:
Given data,
The initial velocity of the airplane, u = 24 m/s
The acceleration of the plane, a = 8 m/s
The distance covered until take off, d = 800 m
Using the III equation of motion,
v² = u² +2as
= 24² + 2 x 8 x 800
= 13376
v = 115.65 m/s
Using the first equation of motion,
v = u + at
t = (v-u) / a
= (115.65 - 24) / 8
= 11.46 s
Hence, the time taken by the airplane to take off, t = 11.46 s
