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3 years ago

Why do you think that scientists in the 20th century thought that it was important to “unlock” the structures of the atom?

Chemistry

1 answer:

Soloha48 [4]3 years ago

7 0

Answer:

The 20th century saw huge advances in our understanding and use of the nucleus. For instance, in 1939 scientists Otto Hahn, Lise Meitner and Otto Frisch discovered nuclear fission – a process by which radioactive materials release energy when they are induced to split.

Realising the huge amount of energy that such a reaction produces, scientists were tasked with developing this new knowledge initially for harm in nuclear weapons. Just six years after fission’s discovery, it was harnessed in the atom bombs that destroyed the Japanese cities Hiroshima and Nagasaki, and controversially ended the Second World War. Later, much more powerful hydrogen bombs were developed that combined fission with the process powering the Sun – fusion.

Hope this helps! PLEASE GIVE ME BRAINLIEST!!!!! =)

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Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone

fenix001 [56]

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

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3 years ago

When substances are evenly spread throughout a mixture, it is called ____________________?

harina [27]

The answer is _Dissolving_.

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3 years ago

Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr

lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C

Using the equation,

Δ $T_{f}$ = i $K_{f}$ m

where:

Δ $T_{f}$ = change in freezing point (unknown)

i = Van't Hoff factor

$K_{f}$ = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = $\frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }$

molal concentration = 0.1219m

Now, putting in the values to the equtaion Δ $T_{f}$ = i $K_{f}$ m we get,

Δ $T_{f}$ = 2 × 1.86 × 0.1219

Δ $T_{f}$ = 0.4536°C

So, Δ $T_{f}$ of solution is,

Δ $T_{f_{solution} }$ = 0.00°C - 0.45°C

Δ $T_{f_{solution} }$ = - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C

Learn more about freezing point here;

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2 years ago

Phương trình hóa học là gì

Doss [256]

Explanation:

sự xuất bản hóa học nào? có một câu hỏi về khoa học mà bạn cần giúp đỡ? tôi luôn ở đây để giúp đỡ!

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2 years ago

Estradiol is a female sexual hormone that causes maturation and maintenance of the female reproductive system. Elemental analysi

Ipatiy [6.2K]

Answer:

The molecular formula of estradiol is: $C_{18}H_{24}O_2$ .

Explanation:

Molar mass of of estradiol = M= 272.37 g/mol

Let the molecular formula of estradiol be $C_xH_yO_z$

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

Percentage of carbon in estradiol :

$\frac{x\times 12 g/mol}{272.37 g/mol}\times 100=79.37\%$

x = 18.0

Percentage of hydrogen in estradiol :

$\frac{y\times 1g/mol}{272.37 g/mol}\times 100=8.88\%$

y = 24.2 ≈ 24

Percentage of oxygen in estradiol :

$\frac{z\times 16 g/mol}{272.37 g/mol}\times 100=11.75\%$

z = 2

The molecular formula of estradiol is: $C_xH_yO_z:C_{18}H_{24}O_2$

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3 years ago