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Naily [24]
3 years ago
13

HELP PLZ ITS DUE SOON!!

Chemistry
1 answer:
sergey [27]3 years ago
7 0
It is the second option! the square with more orange dots will have to move over so that there is an equal amount or equilibrium! another way to look at it is, if we just moved the one dot on the left side then that side would be empty and there would not be equilibrium
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Is albert better grffffrr#fffffrttt
Nezavi [6.7K]

Answer:

yes, albert is better grffffrr#fffffrttt.

Explanation:

4 0
3 years ago
Read 2 more answers
Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.35 atm at a
Luden [163]

Answer : The mass of NaN_3 at temperature 20^oC 28.47 g.

The mass of NaN_3 at temperature 10^oC 29.51 g.

Solution : Given,

Pressure of gas = 1.35 atm

Temperature of gas = 20^oC=273+20=293K     (0^oC=273K)

Volume of gas = 25\times 25\times 20cm=12500cm^3=12.5L   (1L=1000cm^3)

Molar mass of NaN_3 = 65 g/mole

Part 1 : First we have to calculate the moles of gas at temperature 20^oC. The gas produced in the given reaction is N_2.

Using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (293K)

By rearranging the terms, we get the value of 'n'

n=0.7015moles

The moles of N_2 = 0.7015 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.7015 moles of N_2 produced from \frac{20}{32}\times 0.7015=0.438 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.438moles)\times (65g/mole)=28.47g

Therefore, the mass of NaN_3 needed are 28.47 g.

Part 2 : We have to calculate the moles of gas at temperature 10^oC and same volume & pressure.

Using ideal gas equation,

PV=nRT

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (283K)

By rearranging the terms, we get the value of 'n'

n=0.726moles

The moles of N_2 = 0.726 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.726 moles of N_2 produced from \frac{20}{32}\times 0.726=0.454 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.454moles)\times (65g/mole)=29.51g

Therefore, the mass of NaN_3 needed are 29.51 g.

7 0
4 years ago
How many grams of calcium carbonate were used if you drew the periodic table on the sidewalk using
german

Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>

The mole of a substance can be calculated as follows:

  • Moles of substance = number of particles/6.02 × 10^23

Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23

Moles of calcium carbonate = 0.25 moles

The mass of calcium carbonate in 0.25 moles is calculated as follows:

  • mass = moles × molar mass

molar mass of a calcium carbonate = 100 g/mol

mass of calcium carbonate = 0.25 × 100 = 25 g.

Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

Learn more about molar mass and mass at: brainly.com/question/15476873

8 0
2 years ago
How can you get the knowledge of minerals chemical makeup or use?
Gre4nikov [31]

A. To determine how to break down minerals


7 0
3 years ago
What is the basic building block of matter
nasty-shy [4]

Answer:

Atoms

Explanation:

Atoms are widely believed to be the most fundamental particle of matter and their basic building blocks. When atoms combines together, they form compounds. Molecules are another units of matter that are made up of tiny particles of atoms.

5 0
4 years ago
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