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slega [8]
2 years ago
12

1. A pure substance contains ONLY one kind of​

Chemistry
1 answer:
mihalych1998 [28]2 years ago
7 0

Answer:

Elements

Explanation:

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What is molarity of a solution containing 0.34 moles of FeCl3 in the 0.45 liters of water
Minchanka [31]
Hello!

Molarity is defined as the number of moles of a substance that can be found in 1 liter of solution. That is expressed mathematically as M=mol/L

For the FeCl₃ solution:

M= \frac{mol FeCl_3}{L sol}= \frac{0,34 moles FeCl_3}{0,45 L}= 0,756 M

So, the concentration of this solution is 0,756 M

Have a nice day!
7 0
3 years ago
How many molecules of water are there in 0.234 L of water
tankabanditka [31]

Answer:

7.82x10^24 molecules of water

Explanation:

H2O=18.015 g/mol   Avogadro's #=6.022x10^23 molecules

0.234L x 1000g/1L x 1 mol H2O/18.015 g x 6.022x10^23 = 7.82x10^23 molecules of water

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2 years ago
Which statement best describes displacement? Check all that apply
Snowcat [4.5K]
ANSWER:
DISPLACEMENT IS THE SHORTEST PATH LENGTH COVERED BY AN OBJECT.
IT IS A VECTOR QUANTITY AS IT NEEDS BOTH DIRECTION AND MAGNITUDE TO MEASURE IT.
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3 0
3 years ago
How many neutrons would be in an atom of Selenium if the mass number for this particular isotope is Se-80?
EleoNora [17]

Answer:2

Explanation:

6 0
2 years ago
The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released f
frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 4.60 atm = 7.59 \times 10^{-3} M

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

\frac{7.59 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.367 g

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 1.28 atm = 2.11 \times 10^{-3} M

\frac{2.11 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.102 g

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

m = 0.367 g - 0.102 g = 0.265 g

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>

5 0
2 years ago
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