1. A pure substance contains ONLY one kind of

What is molarity of a solution containing 0.34 moles of FeCl3 in the 0.45 liters of water

Minchanka [31]

Hello!

Molarity is defined as the number of moles of a substance that can be found in 1 liter of solution. That is expressed mathematically as M=mol/L

For the FeCl₃ solution:

$M= \frac{mol FeCl_3}{L sol}= \frac{0,34 moles FeCl_3}{0,45 L}= 0,756 M$

So, the concentration of this solution is 0,756 M

Have a nice day!

7 0

3 years ago

How many molecules of water are there in 0.234 L of water

tankabanditka [31]

Answer:

7.82x10^24 molecules of water

Explanation:

H2O=18.015 g/mol Avogadro's #=6.022x10^23 molecules

0.234L x 1000g/1L x 1 mol H2O/18.015 g x 6.022x10^23 = 7.82x10^23 molecules of water

3 0

2 years ago

Which statement best describes displacement? Check all that apply

Snowcat [4.5K]

ANSWER:
DISPLACEMENT IS THE SHORTEST PATH LENGTH COVERED BY AN OBJECT.
IT IS A VECTOR QUANTITY AS IT NEEDS BOTH DIRECTION AND MAGNITUDE TO MEASURE IT.
HOPE IT HELPS!!!
IF IT HELPS PLEASE MARK BRAINLIEST!!!!

3 0

3 years ago

How many neutrons would be in an atom of Selenium if the mass number for this particular isotope is Se-80?

EleoNora [17]

Answer:2

Explanation:

6 0

3 years ago

The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released f

frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

$C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 4.60 atm = 7.59 \times 10^{-3} M$

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

$\frac{7.59 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.367 g$

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

$C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 1.28 atm = 2.11 \times 10^{-3} M$

$\frac{2.11 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.102 g$

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

$m = 0.367 g - 0.102 g = 0.265 g$

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>

5 0

2 years ago

1. A pure substance contains ONLY one kind of​

1. A pure substance contains ONLY one kind of