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andreyandreev [35.5K]
3 years ago
13

Cual es el tamaño de partícula del alcohol

Chemistry
1 answer:
salantis [7]3 years ago
4 0

Answer:

Las botellas de alcohol vienen en una variedad de tamaños. El estándar es de 750 ml, que también se conoce como "un quinto" porque es 1/5 de galón. Otros tamaños comunes de botellas de alcohol son 50ml, 100ml, 200ml, 375ml, 1L y 1.75L.

Explanation:

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Nady [450]
3
One from fe
And two from cl2
7 0
3 years ago
The first question is the one I need help with
aleksandr82 [10.1K]

I looked at the question and there isn't a lot of information. im assuming the answer is carbon dioxide. its the only substance that would make sense I hope it helps.


5 0
4 years ago
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

n=0.406mole

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

As, 1 mole of CH_4 react with 2 moles of O_2

So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

7 0
3 years ago
To 225 mL of a 0. 80 M solution of Kl, a student adds enough water to make 1. 0 L of a more dilute Kl solution. What is the mola
Lady_Fox [76]

Answer: 0.18 M

Explanation:

Initial molarity, M1 = 0.8 M

Initial olume, V1 = 225 ml

Final volume, V2 = 1000 ml

Final Molarity, M2 = M1V1/V2

= 0.8 x 225/1000

= 0.18 M

7 0
2 years ago
Which transformation of energy occurs in a hydroelectric power plant?
Ber [7]
The answer for this question is D.
5 0
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