½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
½H2(g) + ½I2(g) + 6,2kcal/mole → HI(g)
________
21.0 kcal/mole + C(s) + 2S(s) → CS2(l)
or...
C(s) + 2S(s) → CS2(l) ΔH = +2,1 kcal/mole
_________
ΔH > 0 ----------->>> ENDOTHERMIC REACTIONS
Answer:
By atomic number?
Explanation:
fingers crossed its right :/
Answer:
orbiting closer to the earth's surface.....im pretty sure abt it
Answer:

Explanation:
Hello!
In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

Best regards!