Answer:
Atomic mass of nitrogen = 14.0067 amu.
Explanation:
Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.
Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).
The two isotopes of nitrogen are nitrogen-14 and nitrogen-15.
Given the following data;
Relative abundance of N-14 = 99.63%
Atomic mass of N-14 = 14.003
Relative abundance of N-15 = 0.37%
Atomic mass of N-15 = 15.000
The atomic mass is;
14.003 × (99.63/100) + 15.000 × (0.37/100)
Atomic mass = 14.003 × (0.9963) + 15.000 × (0.0037)
Atomic mass = 13.9512 + 0.0555
Atomic mass = 14.0067 amu.
<em>Therefore, the atomic mass of nitrogen is 14.0067 amu. </em>
I think it's 2:1 or 2:1:4. I mostly think it's 2:1 though. (:
Answer:
34.6 cm³
Explanation:
<em>A chemistry student needs 55.0 g of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is 1.59 g/cm³. Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of carbon tetrachloride (m): 55.0 g
- Density of carbon tetrachloride (ρ): 1.59 g/cm³
Step 2: Calculate the required volume of carbon tetrachloride
Density is an intrinsic property of matter. It can be calculated as the quotient between the mass of the sample and its volume.
ρ = m/V
V = m/ρ
V = 55.0 g/(1.59 g/cm³)
V = 34.6 cm³
The chemistry student should pour 34.6 cm³ of carbon tetrachloride.
Hello!
Reading the worksheet shows you how to find the concentration of liquid water in a substance, but when converting a decimal to a percentage, remember that ALL percentages are out of 100, so, we multiply the decimal by 100 to convert it into a percentage.
Liquid A: total amount: 10 millimeters & amount of water: 7 millimeters
7/10 = 0.7 × 100 = 70%
Liquid B: total amount: 100 millimeters & amount of water: 92 millimeters
92/100 = 0.92 × 100 = 92%
Liquid C: total amount: 15 millimeters & amount of water: 13 millimeters
13/15 = 0.867 × 100 = 86.7%
Liquid D: total amount: 28 millimeters & amount of water: 22 millimeters
22/28 = 0.786 × 100 = 78.6%
<u>Final answers</u>:
- Liquid A: 70%
- Liquid B: 92%
- Liquid C: 86.7%
- Liquid D: 78.6%
Answer:
Im bad at these questions but i think the answer is SrBr2
Explanation:
