Answer:
modular
Explanation:
<em>The addition of extra liquid protein supplement to the tube feeding formula of Alice is an example of modular formula.</em>
<u>A modular formula consists of a deficient food supplements that is specifically rich in a particular macronutrient such as protein, carbohydrate, etc. </u>
The supplements in modular formula are usually in liquid from and are introduced into the tube feeding formula of a patient undergoing tube feeding.
In this case, the macronutrient in the liquid food supplement being given to Alice is protein.
Answer:
* No precipitate: 
* Precipitate: 
* Precipitate: 
Explanation:
Hello!
In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:
a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:
b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:
c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:
Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.
Best regards!
Answer:
c
Explanation:
you don't think of particles as dense and less dense
dust particles containvenergy but won't release it unless acted upon a force
gas molecules move freely and collide with dust particles which is correct
C.
Water is polar because one side of the molecule is positive and the other is negative.
Answer:
ΔT = 0.78 °C
Explanation:
Given data:
Mass of Al = 9.5 g
Specific heat capacity of Al = 0.9 J/g.°C
Temperature change = ?
Heat added = 67 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
67 J = 9.5 g × 0.9 j/g.°C × ΔT
67 J = 85.5 j/°C × ΔT
ΔT = 67 J / 85.5 j/°C
ΔT = 0.78 °C
