Answer:
The intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.
Explanation:
The intensity of sound is given by;
where;
I is the intensity of the sound
I₀ is the threshold of sound intensity = 1 x 10⁻¹² W/m²
The intensity of sound at a rock concert
The intensity of sound of a whisper
Thus, the intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.
Answer:
The speed of the object is ()m/s
The magnitude of the acceleration is 4.00m/s²
Explanation:
Given - position vector;
r = (2.0 + 3.00t)i + (3.0 - 2.00t²)j -------------------(i)
To get the speed vector (), take the first derivative of equation (i) with respect to time t as follows;
=
=
=
------------------------(ii)
To get the acceleration vector (), take the first derivative of the speed vector in equation(ii) as follows;
j
The magnitude of the acceleration |a| is therefore given by
|a| = |-4.00|
|a| = 4.00 m/s²
In conclusion;
the speed of the object is ()m/s
the magnitude of the acceleration is 4.00m/s²
Explanation:
Given that,
Mass of a body, m = 1 kg
Force constant, k = 16 N/m
We need to find the angular frequency and the frequency of oscillation.
(a) The angular frequency of a body is given by :
(b) The frequency of oscillation is given by :
Hence, this is the required solution.