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erik [133]
3 years ago
9

Does high pressure rise and low pressure sink

Physics
2 answers:
sergeinik [125]3 years ago
6 0
High pressure<span> is associated with sinking air, and </span>low pressure<span> is associated with </span>rising air t<span>he opposite occurs with </span>high pressure<span>. Air is moving away from the </span>high pressure<span> center at the surface so as a result, air from above must </span>sink <span>to take its place.</span>
Amiraneli [1.4K]3 years ago
5 0
Low rises high sinks
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The latent heat of fusion of alcohol is 50 kcal/kg and its melting point is -54oC. It has a specific heat of 0.60 in its liquid
sashaice [31]

Answer:

C

Explanation:

To melt the alcohol

Heat needed = M . L  = 2 . 25  = 50 kcal

To warm up the alcohol

Heat needed = M . sp. ht. . ∆t   = 2 . 0.6 . 100  = 120 kcal

Total heat needed = 170 kcal

Assuming that 0.6 kcal/ kg / ˚C  is the specific heat and that the answer is wanted in kcal ( a rather odd unit to be in use here.)

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A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
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Answer:

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V = 2.8 cm/sec

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2 years ago
Ways that industry and agriculture use physical properties to separate substances
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They use size and weight

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3 years ago
A car at the top of a ramp starts from rest and rolls to the bottom of the ramp, achieving a certain final speed. If you instead
zimovet [89]

Answer:

It must be 4 times high.

Explanation:

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  • This means, that at any time, the following must be true:
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⇒      m*g*h = \frac{1}{2} * m*v^{2}

  • Let's call v₁, to the final speed of the car, and h₁ to the height of the ramp.

       So, at the bottom of the ramp, all the gravitational potential energy

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       m*g*h_{1}  = \frac{1}{2} * m*v_{1} ^{2}  (1)

  • Now, let's do v₂ = 2* v₁
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        m*g*h_{2}  = \frac{1}{2} * m*(2*v_{1}) ^{2} (2)

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8 0
3 years ago
Show the equation of simple pendulum to be dimensionally consistent
nataly862011 [7]
T is in seconds (s) 

<span>2pi is dimensionless </span>

<span>L is in meters (m) </span>

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<span>s=sqrt(m/(m/s^2)) </span>

<span>simplify</span>

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<span>therefore the dimensions on the left side of the equation are equal to the dimensions on the right side of the equation.</span>
6 0
3 years ago
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