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2 years ago

Explain what happens to the concentrations of the reactants and products during a chemical reaction

Chemistry

1 answer:

stira [4]2 years ago

3 0

The concentration of reactants decreases and the concentration of products increases. :)

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2. Lysosomes operate within the cell bye to the

Marat540 [252]

Answer:

Explanation:

Lysosomes contain digestive enzymes which are used for digestion of food and dead organelles. It fuses with a vacuole which contain the targeted material(food or dead organelles) and digests the material inside it

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3 years ago

Name 5 things that the periodic table includes about 1 atom for each element:

olganol [36]

Answer:

They are listed below

Explanation:

The 5 things that the periodic table includes are;

1. Name of the element

2. The symbol of the element

3. Atomic number of the element

4. Relative atomic mass

5. Electron configuration

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2 years ago

What is the approximate pressure of a storage cylinder of recovered R-404A that does not contain any non-condensable impurities

gregori [183]

Answer:

288 psig

Explanation:

4 0

3 years ago

Read 2 more answers

g Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no r

Mrac [35]

Answer:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

Explanation:

We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

You may know these information:

Salts from acetate are soluble.

Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

PbBr₂ is formed, so this will be our precipitate

The equation is:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

8 0

2 years ago

Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

3 0

2 years ago