All categories

1 year ago

13. What does 2n^2 stand for?

Chemistry

1 answer:

Sever21 [200]1 year ago

4 0

Answer:

2n² is a formula that determines that the maximum number of electrons should be accommodated in a particular shell.

Explanation:

You might be interested in

What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4

valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

$k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}$

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]= $\sqrt{ 0.3*7.42x10^{-4}}$

[OH-]=0.01

pH=14-(-log[OH-])

pH=12

5 0

2 years ago

A balloon that has a volume of 9.45L of helium is released at the ground where the pressure is 760mmHg. What is the volume of th

max2010maxim [7]

Answer:

What is the volume of the balloon when it rises in the atmosphere to a place where pressure is 640mmHg

4 0

1 year ago

One type of cat has the scientific name Felis domesticus, while another type of cat is called Felis tigris. What can be correctl

kykrilka [37]

A is the correct answer

3 0

2 years ago

How many moles of oxygen gas are there in 395 L of oxygen at STP?

kozerog [31]

Answer:

17.6 moles of oxygen gas.

Explanation:

STP Variables:

P=1 atm

R=0.082

T=273 K

Use the PV=nRT, then plug in.

n=PV/RT

n= (1 atm)(395 L)/(0.082) (273 K)

Simplify.

n=17.6 moles of O2

Hoped this helped.

7 0

2 years ago

(20 points) i) An absorption intensity of 1.00 (in arbitrary units) is observed for the maximum peak of the 1:2:1 triplet of the

laiz [17]

Answer:

Concentration of ethanol required = 48.476 M

Explanation:

Given that:

the absorption intensity = 1.00

Molarity of ethanol = 1M

NMR instrument used = 160 MHz

Temperature used = 300 K

The required concentration of ethanol can be determined as follows:

$= ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}$

$= ( 1 \ M \times 0.3555 ) \times136.36}$

= 48.476 M

5 0

2 years ago