Answer:
In the presence of salt water and oxygen the coating will not corrode. As long as zinc coating is present and remains intact corrosion is not possible.
Explanation:
Here it is given that a tin is present so firstly tin is made of a chemical element
which belongs to carbon family in periodic table of group 14.
It is a silvery,soft, white metal with a bluish tinge.
Now the covering which is been done on the tin is Zinc.
so, zinc is known to be served as a sacrificial coater.
Their is an amazing reason behind zinc coating being so effective and intact i.e. Its own corrosive properties are such that it stops corrosion.
Their is a process which is known as a galvanic corrosion which refers to that "ZINC" defers to the metal to which it is protecting.
It is even more electrochemically active than iron itself.
Here, it is mentioned that zinc coating gets chipped but the coating remains intact. So, if the zinc is not removed from the tin's surface it will not get corroded when it is exposed to salt water and oxygen.
Answer:
a,b,e,f,g
Explanation:
Hydrogen bonding is an intermolecular force of attraction between two molecules. It is a special type of dipole-dipole attraction.
In hydrogen bonding, the hydrogen on one molecule binds with an electronegative atom on another molecule usually oxygen, nitrogen and fluorine.
The simple electrostatic attraction leads to strong intermolecular interaction between two molecules.
For the formation of hydrogen bond, a hydrogen atom must be bonded to more electronegative specie usually N, O and F
In H₂O and H₂O₂ ; hydrogen bonds with Oxygen
CH₃NH₂; hydrogen is attached to nitrogen
HF; hydrogen is attached to fluorine
CH₃OH; hydrogen is attached to oxygen
The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
= 0.200 × 0.039 l
= 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be;
= (0.0156 × 1)/0.1
= 0.156 M
Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below.
N2(g) + 3H2(g) = 2NH3(g)
1 mole of ammonia contains 17 g
Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles
The mole ratio of hydrogen to ammonia is 3 : 2
Therefore, moles of hydrogen used will be 0.6341 × 3/2 = 0.9512 moles
1 mole of hydrogen is equivalent to 2 g
Thus, the mas of hydrogen will be 0.9512 moles × 2 = 1.9023 g
It's D because I know bcz I'm smart 8 times 8 is 60-nart
