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LiRa [457]
2 years ago
7

Which organisms in the food web shown compete for the same food source in this environment?

Chemistry
1 answer:
11111nata11111 [884]2 years ago
3 0

Answer:

there is no photo

Explanation:

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Classify each of the following reactants and products as an acid or base according to the Bronsted theory: H3PO4 + C6H5O- <=&
Alexxandr [17]

Answer:

H₃PO₄ is an acid because donates the proton to fenolate.

Fenolate is the base because accepts the proton from the acid.

Explanation:

Bronsted theory mentioned that acid is the one that donates a proton to another compound and base is the one that receives it.

H₃PO₄   +   C₆H₅O⁻    ⇄      H₂PO₄⁻      +       C₆H₅OH

acid              base              conj. base            conj. acid

H₃PO₄ is an acid because donates the proton to fenolate.

Fenolate is the base because accepts the proton from the acid.

If we follow the dissociation, the diacid phosphate can donate two more protons, it is still a Bronsted acid, but it can act as an acid or a base. This is called amphoteric.

6 0
3 years ago
Which row probably contains the largest atoms on the periodic table?
svp [43]
The last row going across
7 0
3 years ago
How do water go to the sky?
Tanya [424]
Water goes into the sky by condensation I think
7 0
3 years ago
Read 2 more answers
The label shown above contains information about some harmful effects of acetone.A group of students plans to use acetone to rin
Fed [463]

Answer:

<u>Heating water with an open flame</u>

<u>Explanation:</u>

Remember, we are told in the label that Acetone is a "flammable liquid and vapor." <em>Being flammable means the substance can easily be set on fire</em>, and we would expect an open flame from heating water to trigger an explosion (a disaster) in which the Acetone is set on fire causing life-threatening dangers to the second group of students.

8 0
3 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
2 years ago
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