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Norma-Jean [14]
3 years ago
6

A light ray is incident from air into glass (ng = 1.52) then onto water (nw= 1.33). The wavelength of light in air (na= 1) is ai

r = 500 nm and it travels at a speed c = 3 x 108 m/s. The wavelength of light, A, and its frequency, f, in water, are, respectively:
(a) 376 nm, 6 x 10¹4 Hz.
(b) 376 nm, 8 x 10¹¹ Hz
(c) 500 nm, 6 x 10¹4 Hz
(d) 500 nm, 8 x 10¹¹ Hz​
Physics
1 answer:
gregori [183]3 years ago
3 0
The answer is is b hope this helped
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An average person can reach a maximum height of about 65 cm when jumping straight up from a crouched position. During the jump i
Yakvenalex [24]

Answer:

a. Initial speed is zero from a crouching position...

b... Mass of body * 9.8

Explanation:

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The outside diameter of your teacher's rear bicycle tire is 16 inches. How far will he travel if the rear wheel makes 1200 revol
FinnZ [79.3K]

Answer:

241,274.32 inches

Explanation:

How far will he travel if the rear wheel makes 1200 revolutions on the road?

Since the rear wheel makes one revolution in the distance of a circumference of a circle, C with diameter, d = 16 inches

C = πd²/4

So, the distance, travelled in 1200 revolutions is D = 1200 × C = 1200πd²/4

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3 years ago
Two protons move with uniform circular motion in the presence of uniform magnetic fields. Proton one moves twice as fast as prot
lubasha [3.4K]

Answer:

r₂ = 4 r

Explanation:

For this exercise let's use Newton's second law with the magnetic force

          F = q v x B

bold letters indicate vectors, the magnitude of this expression is

          F = q v B sin θ  

in this case we assume that the angle is 90º between the speed and the magnetic field.

If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal

           a = v² / r

let's use Newton's second law

           F = ma

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           r = \frac{qB}{mv}

Let's apply this expression to our case.

Proton 1

             r = \frac{qB_1}{mv_1}

Proton 2

             r₂ = \frac{q \ B_2}{m \  v_2}

in the exercise indicate some relationships between the two protons

*    v₁ = 2 v₂

    v₂ = v₁ / 2

*   B₂ = 2B₁

we substitute

           r₂ = \frac{q \ 2B_1}{m \ \frac{v_1}{2} }

           r₂ = 4 \frac{qB_1}{mv_1}

           r₂ = 4 r

7 0
3 years ago
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They have a different number neutrons.
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What falls faster? Light or heavy objects?
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Heaver objects because they have greater mass  
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