Hello!

We can begin by solving for c₃ given the equations:
c₃ = 3c₂ + 2c₁ - 2
c₃ = 3(2) + 2(4) - 2
Simplify:
c₃ = 6 + 8 - 2 = 12
We can now find the subsequent terms:
c₄ = 3(12) + 2(2) - 2 = 38
c₅ = 3(38) + 2(12) - 2 = 136
-3y≥72
divide both side by (-3)
-3y/-3 >= 72/-3
Simplify
y >= -24
The midpoint divided a segment into two congruent lengths/segments.
So, QM = MR.
Set up the equation.
16 + x = 2(x+ 2)
16 + x = 2x + 4
12 + x = 2x
12 = x
Now, that you have the value of x, substitute it for the two equations.
QM = 16 + x
QM = 16 + 12
QM = 28
MR = 2(12+ 2)
MR = 2(14)
MR = 28
Find the whole length by of the line by adding the two segments. 28 × 2 = 56.
QR = 56
Theres no answer to this promblem do you wanna add more