Fitness is more accurately described as habit, so it is achieved only through A. frequency<span>. In order to achieve results in fitness, one must be consistent with exercise and nutrition. Not only is this the means to achieving fitness, this is also the way that fitness is maintained. </span>
Answer:
50.97 m
Explanation:
m = Mass of truck
= Coefficient of static friction = 0.4
v = Final velocity = 0
u = Initial velocity = 72 km/h = 
s = Displacement
Force applied

Frictional force

Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide

Since the obect will be decelerating the acceleration will be 
From the kinematic equations we have

So, the minimum distance at which the car will stop without making the load shift is 50.97 m.
The equation of the motion of this object is ![\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%203%20cos%20%5CBig%20%5B%20%5Cdfrac%7B%20%5Cpi%7D%7B2%7D%28t%20-2%29%20%5CBig%20%5D%20%7D)
<h3>What is oscillation?</h3>
An oscillation in a waveform is a periodic set of vibrations an object in the medium produces.
From the parameters given:
- The spring is pulled 3 feet down ward from the origin(equilibrium position) = -3
- Time to complete one oscillation = 4 seconds
The angular velocity can be computed by using the formula:


The amplitude A from the oscillation is:

It implies that the vertical shift (D) is:

However, by using the formula of the general form of a sinusoidal equation, we have:
![\mathbf{y = A cos \Big [ \dfrac{2 \pi}{4}(t -2) \Big ] + 0}](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%20A%20cos%20%5CBig%20%5B%20%5Cdfrac%7B2%20%5Cpi%7D%7B4%7D%28t%20-2%29%20%5CBig%20%5D%20%2B%200%7D)
![\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%203%20cos%20%5CBig%20%5B%20%5Cdfrac%7B%20%5Cpi%7D%7B2%7D%28t%20-2%29%20%5CBig%20%5D%20%7D)
Learn more about oscillation in waveform here:
brainly.com/question/15701473
Answer:
v = 1176.23 m/s
y = 741192.997 m = 741.19 km
Explanation:
Given
M₀ = 9 Kg (Initial mass)
me = 0.225 Kg/s (Rate of fuel consumption)
ve = 1980 m/s (Exhaust velocity relative to rocket, leaving at atmospheric pressure)
v = ? if t = 20 s
y = ?
We use the equation
v = ∫((ve*me)/(M₀ - me*t)) dt - ∫g dt where t ∈ (0, t)
⇒ v = - ve*Ln ((M₀ - me*t)/M₀) - g*t
then we have
v = - 1980 m/s*Ln ((9 Kg - 0.225 Kg/s*20 s)/(9 Kg)) - (9.81 m/s²)(20 s)
v = 1176.23 m/s
then we apply the formula
y = ∫v dt = ∫(- ve*Ln ((M₀ - me*t)/M₀) - g*t) dt
⇒ y = - ve* ∫ Ln ((M₀ - me*t)/M₀) dt - g*∫t dt
⇒ y = - ve*(Ln((M₀ - me*t)/M₀)*t + (M₀/me)*(M₀ - me*t - M₀*Ln(M₀ - me*t))) - (g*t²/2)
For t = 20 s we have
y = Ln((9 Kg - 0.225 Kg/s*20 s)/9 Kg)*(20 s) + (9 Kg/0.225 Kg/s)*(9 Kg - 0.225 Kg/s*20 s - 9 Kg*Ln(9 Kg - 0.225 Kg/s*20 s)) - (9.81 m/s²*(20 s)²/2)
⇒ y = 741192.997 m = 741.19 km
The graphs are shown in the pics.
<span>A.
Gravitational force is proportional to the square of the distance
between the centers of both bodies.
FALSE:
Gravitational force is inversely proportional to the square of the distance between the centers of both bodies.
Which you can see from the formula: F = G * [m*M] /(d^2)
As you see in the equation, d^2 is in the denominator so the bigger d^2 (the square of the distance between the centers) of the objects the smaller the gravitational force.
B. The object with the smaller mass
does most of the moving because the object with the larger mass has too
much inertia to move any noticeable amount.
TRUE:
F = mass * acceleration => acceleration = F / mass => the larger the mass the smaller the acceleration.
C. Gravitational force is
proportional to the product of the two masses.
TRUE:
F = G [m*M] / (d^2)
The product of the two masses, m*M, is in the numerator, so F is proportional to this product.
D. Every object in the
universe that has mass attracts every other object in the universe that
has mass.
TRUE: that is a Universal Law discovered by Sir Isaac Newton.
</span>