Newton's 2nd law of motion:
Force = (mass) x (acceleration)
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(1,500 kg) x (7 m/s²) = 10,500 newtons .
The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.
v = 10m/s
d = 462m
v = d/t
(10) = (462)/t
t = 46.2s
So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:
v = 35m/s
v = d/t
(35) = d/(46.2)
d = 1617m
Car 1 traveled a total distance of 1617m.
