Answer:
eccentrcity of orbit is 0.22
Explanation:
GIVEN DATA:
Initial velocity of satellite = 8333.3 m/s
distance from the sun is 600 km
radius of earth is 6378 km
as satellite is acting parallel to the earth therefore
and radial component of given velocity is zero
we have
h = 6.97*10^6 *8333.3 = 58.08*10^9 m^2/s
we know that
so
solvingt for
therefore eccentrcity of orbit is 0.22
Answer:
Inside the Sun.
Explanation:
Inside the Sun, this process begins with protons (which is simply a lone hydrogen nucleus) and through a series of steps, these protons fuse together and are turned into helium. This fusion process occurs inside the core of the Sun, and the transformation results in a release of energy that keeps the sun hot.
Answer:
a
The poles and corresponds to the short period mode
b
The poles and corresponds to the phugoid mode
Explanation:
The explanation is shown on the first and second uploaded image
clean the tubes and fins with a high-pressure jet of air or mechanical scrubbing
ensure that the condenser fans are operating properly
The answer would be for a .7 and b is 1.3 and c is .8