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victus00 [196]
3 years ago
12

6.39 A particular machine part is subjected in service to a maximum load of 10 kN. With the thought of providing a safety factor

of 1.5, it is designed to withstand a load of 15 kN. If the maximum load encountered in various applications is normally distributed with a standard deviation of 2 kN, and if part strength is normally distributed with a standard deviation of 1.5 kN, what failure percentage would be expected in service? [Ans.: 2.3%]

Engineering
1 answer:
Serggg [28]3 years ago
8 0

Answer:

2.275 %

Explanation:

see the attached picture for detailed answer.

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3 years ago
A ship tows a submerged cylinder, 1.5 m in diameter and 22 m long, at U = 5 m/s in fresh water at 20°C. Estimate the towing powe
shusha [124]

Answer:

(a) 120 kW

(b) 800 kW

Explanation:

Given:

diameter: 1.5 m

length = 22 m

U = 5 m/s

temperature = 20°C

For water at 20°C, take ρ = 998 kg/m³  and µ = 0.001 kg/m⋅s

To find:

power in kW

(a) if the cylinder is parallel

Length / Diameter = L / D = 22 / 1.5 = 14.6 = 15

Re(L) = ρ*U*L / µ = 998 * 5 * 22 / 0.001 = 109780000 = 1.1E8

C(D.Frontal) ≈ 1.1

  Force = F = 1.1 * ρ/2 * U² * π / 4 * D

            =  1.1 (998 / 2) (5)²(π / 4)(1.5)²  

            = 1.1 * 499 * 25 * 0.785 * 2.25

            = 24000 N

Power = Force * Displacement / time

           = F * U

           = 24000 * 5

           = 120000

Power = 120 kW

b) if the cylinder is normal to the tow direction.

Re(L) = ρ*U*D / µ = 998 * 5 * 1.5 / 0.001 = 7485000 = 7.5E6

C(D.Frontal) ≈ 0.4

Force = F = 0.4 * ρ/2 * U² * D * L

            =  0.4 (998 / 2) (5)²(1.5)(22)  

            = 164670 ≈ 165000

Power = Force * Displacement / time

           = F * U

           = 165000 * 5 = 825000

           ≈ 800 kW

Power = 800 kW

7 0
4 years ago
Estimate horizontal and vertical tail sizes fo r a twin-turboprop regional transport with wing area of 40 m2, aspect ratio of 10
svetlana [45]

Answer: 0.2m sqr

Explanation:

A well behaved aircraft basically have a value of volume in horizontal and vertical area.

Volume in horizontal area (Vh) = 0.6

Volume in vertical area (Vv) = 0.05

Having known this, consider the relationship to find the vertical and horizontal tail sizes.

Vertical tail area (Sv)

Horizontal tail area (Sh)

Vh= (Sh × I) / S

Where,

I = moment

S= wing area

Sh= Horizontal tail area

Vh= Volume in horizontal area

0.6= Sh × 10/40

24= 10Sh

Sh= 24/10

Sh= 2.4 msqr

Horizontal tail area= 2.4m sqr

From the information above, we can calculate the vertical tail area.

Vertical tail area is calculated thus below:

Vv= (Sv× I) / S

Where

Vv= Volume in vertical area

Sv= Vertical tail area

I= Moment

S= Wing area

Therefore

Sv= (Vv × S) /I

Sv= (0.05×40)/10

Sv= 0.2msqr

In conclusion, the vertical tail size is 0.2msqr

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3 years ago
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