Answer:
Check the explanation
Explanation:
Code
.ORIG x4000
;load index
LD R1, IND
;increment R1
ADD R1, R1, #1
;store it in ind
ST R1, IND
;Loop to fill the remaining array
TEST LD R1, IND
;load 10
LD R2, NUM
;find tw0\'s complement
NOT R2, R2
ADD R2, R2, #1
;(IND-NUM)
ADD R1, R1, R2
;check (IND-NUM)>=0
BRzp GETELEM
;Get array base
LEA R0, ARRAY
;load index
LD R1, IND
;increment index
ADD R0, R0, R1
;store value in array
STR R1, R0,#0
;increment part
INCR
;Increment index
ADD R1, R1, #1
;store it in index
ST R1, IND
;go to test
BR TEST
;get the 6 in R2
;load base address
GETELEM LEA R0, ARRAY
;Set R1=0
AND R1, R1,#0
;Add R1 with 6
ADD R1, R1, #6
;Get the address
ADD R0, R0, R1
;Load the 6th element into R2
LDR R2, R0,#0
;Display array contents
PRINT
;set R1 = 0
AND R1, R1, #0
;Loop
;Get index
TOP ST R1, IND
;Load num
LD R3,NUM
;Find 2\'s complement
NOT R3, R3
ADD R3, R3,#1
;Find (IND-NUM)
ADD R1, R1,R3
;repeat until (IND-NUM)>=0
BRzp DONE
;load array address
LEA R0, ARRAY
;load index
LD R1, IND
;find address
ADD R3, R0, R1
;load value
LDR R1, R3,#0
;load 0x0030
LD R3, HEX
;convert value to hexadecimal
ADD R0, R1, R3
;display number
OUT
;GEt index
LD R1, IND
;increment index
ADD R1, R1, #1
;go to top
BR TOP
;stop
DONE HALT
;declaring variables
;set limit
NUM .FILL 10
;create array
ARRAY .BLKW 10 #0
;variable for index
IND .FILL 0
;hexadecimal value
HEX .FILL x0030
;stop
.END
the required documents is 3000
Answer:
camshaft, in internal-combustion engines, rotating shaft with attached disks of irregular shape (the cams), which actuate the intake and exhaust valves of the cylinders.
Explanation:
I'm taking an engineering/tech class. I hope this helps! :)
Answer:
![M=0.0411 kg/h or 4.1*10^{-2} kg/h](https://tex.z-dn.net/?f=M%3D0.0411%20kg%2Fh%20or%204.1%2A10%5E%7B-2%7D%20kg%2Fh)
Explanation:
We have to combine the following formula to find the mass yield:
![M=JAt](https://tex.z-dn.net/?f=M%3DJAt%20)
![M=-DAt(ΔC/Δx)](https://tex.z-dn.net/?f=M%3D-DAt%28%CE%94C%2F%CE%94x%29)
The diffusion coefficient : ![D=6.0*10^{-8} m/s^{2}](https://tex.z-dn.net/?f=D%3D6.0%2A10%5E%7B-8%7D%20m%2Fs%5E%7B2%7D)
The area : ![A=0.25 m^{2}](https://tex.z-dn.net/?f=A%3D0.25%20m%5E%7B2%7D)
Time : ![t=3600 s/h](https://tex.z-dn.net/?f=t%3D3600%20s%2Fh)
ΔC: ![(0.64-3.0)kg/m^{3}](https://tex.z-dn.net/?f=%280.64-3.0%29kg%2Fm%5E%7B3%7D)
Δx: ![3.1*10^{-3}m](https://tex.z-dn.net/?f=3.1%2A10%5E%7B-3%7Dm)
Now substitute the values
![M=-DAt(ΔC/Δx)](https://tex.z-dn.net/?f=M%3D-DAt%28%CE%94C%2F%CE%94x%29)
![M=-(6.0*10^{-8} m/s^{2})(0.25 m^{2})(3600 s/h)[(0.64-3.0kg/m^{3})(3.1*10^{-3}m)]](https://tex.z-dn.net/?f=M%3D-%286.0%2A10%5E%7B-8%7D%20m%2Fs%5E%7B2%7D%29%280.25%20m%5E%7B2%7D%29%283600%20s%2Fh%29%5B%280.64-3.0kg%2Fm%5E%7B3%7D%29%283.1%2A10%5E%7B-3%7Dm%29%5D)
![M=0.0411 kg/h or 4.1*10^{-2} kg/h](https://tex.z-dn.net/?f=M%3D0.0411%20kg%2Fh%20or%204.1%2A10%5E%7B-2%7D%20kg%2Fh)
Answer:
There are six conditions
1. Poles should contain some residual flux.
2. Field and armature winding must be correctly connected so that initial mmm adds residual flux.
3. Resistance of field winding must be less than critical resistance.
4. Speed of prime mover of generator must be above critical speed.
5. Generator must be on load.
6. Brushes must have proper contact with commutators.
Explanation: