For this problem, calculate the following by hand and show the procedure for how you obtained the results. Subsequently, solve p
arts (a-d) using MATLAB and include your MATLAB code in your submission. a) Determine the inner product of vectors a and b. b) Determine the outer (cross) product of vectors a and b. c) Calculate norm (magnitude) of vector c. d) Calculate the determinant of 3x3 matrix A, in which the first column is vector a, second column is vector b, and the third column is vector c. e) Determine if vectors a, b and c are linearly independent.
1 answer:
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Answer:
ummm why is you doing this
Explanation:
It doesnt make sense.
Third one
15,000,000 ohms because M=10^6
Answer:
the answer is
Explanation:
<h2>
We now focus on purely two-dimensional flows, in which the velocity takes the form
</h2><h2>
u(x, y, t) = u(x, y, t)i + v(x, y, t)j. (2.1)
</h2><h2>
With the velocity given by (2.1), the vorticity takes the form
</h2><h2>
ω = ∇ × u =
</h2><h2>
</h2><h2>
∂v
</h2><h2>
∂x −
</h2><h2>
∂u
</h2><h2>
∂y
</h2><h2>
k. (2.2)
</h2><h2>
We assume throughout that the flow is irrotational, i.e. that ∇ × u ≡ 0 and hence
</h2><h2>
∂v
</h2><h2>
∂x −
</h2><h2>
∂u
</h2><h2>
∂y = 0. (2.3)
</h2><h2>
We have already shown in Section 1 that this condition implies the existence of a velocity
</h2><h2>
potential φ such that u ≡ ∇φ, that is
</h2><h2>
u =
</h2><h2>
∂φ
</h2><h2>
∂x, v =
</h2><h2>
∂φ
</h2><h2>
∂y . (2.4)
</h2><h2>
We also recall the definition of φ as
</h2><h2>
φ(x, y, t) = φ0(t) + Z x
</h2><h2>
0
</h2><h2>
u · dx = φ0(t) + Z x
</h2><h2>
0
</h2><h2>
(u dx + v dy), (2.5)
</h2><h2>
where the scalar function φ0(t) is arbitrary, and the value of φ(x, y, t) is independent
</h2><h2>
of the integration path chosen to join the origin 0 to the point x = (x, y). This fact is
</h2><h2>
even easier to establish when we restrict our attention to two dimensions. If we consider
</h2><h2>
two alternative paths, whose union forms a simple closed contour C in the (x, y)-plane,
</h2><h2>
Green’s Theorem implies that
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2>
Answer:
Contaminated sharps should not be bent, recapped or removed.
Explanation:
Contaminated sharps are defined as "any contaminated object that can penetrate the skin including, but not limited to, needles, scalpels, broken glass, broken capillary tubes and exposed ends of dental wires".
Answer:
a) zero b) zero
Explanation:
Newton's first law tells us that a body remains at rest or in uniform rectilinear motion, if a net force is not applied on it, that is, if there are no applied forces or If the sum of forces acting is zero. In this case there is a body that moves with uniform rectilinear motion which implies that there is no net force.
