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2 years ago

Matthew sorts some figures. He includes a regular hexagon with only figures 2 and 3.

Mathematics

1 answer:

kykrilka [37]2 years ago

3 0

Answer:

Step-by-step explanation:

A regular hexagon, a rectangle, and a regular parallelogram all have at least 2 pairs of parallel sides. The sides opposite of each other are parallel. A trapezoidal only has one pair of parallel lines and a kite has 0 parallel sides.

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Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi.

Gnesinka [82]

The answer for this will be letter d. C = 22π and A = 121π. This is computed using the formula of C= Dπ which is C = (22)π. On the other hand, the area of this circle is computed by using the formula A = πr^2. This is computed as follows:
A = πr^2
A = π (22/2)^2
A = π (11)^2
A = 121π

4 0

3 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

$= x {}^{9} y {}^{ - 8}$

$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4} n {}^{ - 1} }{m {}^{ - 5}n {}^{3} } = - 2m {}^{9} n {}^{ - 4}$

$= - \frac{2m {}^{9} }{n {}^{4} }$

14.

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

$( - {x}^{5} y {}^{ - 2} ) {}^{3} = - x {}^{15} y {}^{ - 6}$

$- \frac{x {}^{15} }{ {y}^{6} }$

15.

$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

16.

$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

6 0

2 years ago

Translate the expression with rational exponents into a radical expression. Simplify if necessary.

mars1129 [50]

Look at the attached picture⤴

Hope it will help u..

6 0

3 years ago

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Can someone please help me with this?? im trying to correct answers and i need help

vivado [14]

Answer:

90° is correct answer. :)

6 0

3 years ago

What is the value of the expression 29-|7-11|

Makovka662 [10]

The value of 29 - |7 - 11| = 25

We have the following expression -

29 - |7 - 11|

We have to find its value.

<h3>Find the value of the expression -</h3><h3>X + | $\pi$ Y | where Y < 0</h3>

We have -

X + | $\pi$ Y |

Since Y < 0 - therefore $\pi$ Y < 0

Now -

|a| = - a { for a < 0}

Therefore -

X - $\pi$ Y

According to the question, we have -

29 - |7 - 11|

29 - | -4 |

29 - 4

Hence, the value of 29 - |7 - 11| = 25

To learn more about Modulus function, visit the link below-

brainly.com/question/13103168

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7 0

1 year ago

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