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harina [27]
3 years ago
11

A man lifts a 5 Newton bag of groceries

Physics
1 answer:
allsm [11]3 years ago
5 0
Well I can’t bee any so the closest one is 6 but the answer should be 6.1 and also I’m a middle schooler so I want to learn more stuff like this but I recommend 4.5
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Which liquid will evaporate the fastest water salt water pepsi and gatorade?
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The liquid that will evaporate the quickest would be water. 
<em>~The rest are mixtures, and have more ingrediants in them, therefore the answer should be water. (in which it has no other ingrediants in it but water itself)</em>
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During the process of psychotherapy, Elaine recovered some long-forgotten and painful memories from her childhood. This experien
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6 0
3 years ago
A tennis ball, 0.314 kg, is accelerated at a rate of 164 m/s2 when hit by a professional tennis player. What force does the play
SVEN [57.7K]
Newton's 2nd law of motion:

                    Force = (mass) x (acceleration)

                             = (0.314 kg) x (164 m/s²)

                             =    51.5 newtons

                         (about 11.6 pounds) .

Notice that the ball is only accelerating while it's in contact with the racket.
The instant the ball loses contact with the racket, it stops accelerating, and
sails off in a straight line at whatever speed it had when it left the strings.
4 0
4 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
Read 2 more answers
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