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3 years ago

When should a line graph be used?

Physics

1 answer:

OLEGan [10]3 years ago

4 0

Answer:

A. When the independent variable is continuous and shows a causal link to the dependent variable.

Explanation:

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

In an experiment , the variable being manipulated by an experimenter is known as an independent variable while the dependent variable is the event expected to change when the independent variable is manipulated

Generally, a line graph should be used when the independent variable is continuous and shows a causal link to the dependent variable.

This ultimately implies that, a line graph should be used when the data changes continuously over time and as such there exist a linear relationship between the data (variables).

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When water (H₂O) freezes into ice, some of the properties have changed. What stays the same?

erastova [34]

Answer:

1st one

identity of the H₂O

When water (H2O) freezes into ice, some of the properties have changed but the identity of the H2O is the same. Explanation; Water can exist in liquid, solid; ice and gaseous state; steam. Freezing occurs when water is continuously cool until it turns to solid ice, water freezes at zero degree Celsius

Hope This Helps

4 0

2 years ago

What negative influences must be avoided to be able to achieve your goal mention at least 3

LuckyWell [14K]

The negative influences that must be avoided in order to achieve your goal are excuses, procrastination and distractions.

<h3>What is negative influence?</h3>

A negative influence is someone or something that induces negative or bad action in someone. This bad influence can create bad energy within and corrupt good mind.

<h3>Three negative influence to avoid</h3>

Avoid excuses
Avoid procrastination
Avoid distractions.

Thus, the negative influences that must be avoided in order to achieve your goal are excuses, procrastination and distractions.

Learn more about negative influences here: brainly.com/question/1666465

6 0

3 years ago

Two a.c V1=100sin(wt) and V2 = 150cos(wt) are fed into one circuit, determine the combined output of the two as a single a.c

Dominik [7]

Answer:

Explanation:

V = 100sin(ωt) + 150cos(ωt)

let x = ωt

V = 100sin(x) + 150cos(x)

a maximum or minimum will occur when the derivative is zero

V' = 100cos(x) - 150sin(x)

0 = 100cos(x) - 150sin(x)

100cos(x) = 150sin(x)

100/150 = sin(x)/cos(x)

0.6667 = tan(x)

x = 0.588 rad

V = 100sin(0.588) + 150cos(0.588)

V = 180.27756

as the maximum will not occur until ωt = 0.588 radians, for a cosine function we subtract that amount as a phase angle φ

V = 180.3 cos(ωt - 0.588)

or as a sine function, the phase angle lags the cosine by a difference of π/2

V = 180.3sin(ωt - (0.588 - π/2)

V = 180.3sin(ωt + 0.983)

7 0

3 years ago

Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.1

ludmilkaskok [199]

Answer:

$1.189eV$

Explanation:

The electric potential energy is the potential energy that results from the Coulomb force and is associated with the configuration of two or more charges. For an electron in the presence of an electric field produced by a proton, the electric potential energy is defined as:

$U=\frac{kq_{e}q_{p}}{r}$

where $q_{e}$ is the electron charge, $q_{p}$ is the proton charge, r is the separation distance between the charges and k is the coulomb constant.

Knowing this, we can calculate how much electric potential energy was lost:

$\Delta U=U_{f}-U{i}\\\Delta U=\frac{kq_{e}q_{p}}{r_{f}}-\frac{kq_{e}q_{p}}{r_{i}}\\\Delta U=kq_{e}q_{p}(\frac{1}{r_{f}}-\frac{1}{r_{i}})\\\Delta U=(8.99*10^9\frac{Nm^2}{C^2})(-1.60*10^{-19}C)(1.60*10^{-19}C)(\frac{1}{0.105*10^{-9}m}-\frac{1}{0.115*10^{-9}m})\\\Delta U=1.90*10^{-19}J*\frac{6.2415*10^{18}eV}{1J}=1.189eV$

5 0

4 years ago

What is meant by specific latent heat of fussion

Lunna [17]

Answer:

Boiling point of water is 100 deg C. It takes about 540 cal to change 1 g of water at the boiling point to 1 g of steam at 100 deg C.

5 0

2 years ago