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3 years ago

When a car's velocity is positive and its acceleration is negative, what is happening to the car's motion?

Physics

1 answer:

Novosadov [1.4K]3 years ago

8 0

Answer:

Assuming rightward is positive, the velocity is positive whenever the car is moving to the right, and the velocity is negative whenever the car is moving to the left. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

Explanation:

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A 0.15 kg ball is moving with a velocity of<br> 35 m/s. Find the momentum of the ball.

GarryVolchara [31]

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

Hope this helps you

4 0

3 years ago

the radius of earth is 6370km and of mars is 3400km. if an object weighs 200N or earth , what will be it's weight on mars. the m

4vir4ik [10]

The weight of the object on mars is about 80n

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3 years ago

The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medi

adoni [48]

Answer:

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), $F_v$ = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

$F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}$

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

$F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}$

Take the ratio of the two forces;

$\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N$

Therefore, the value of new coulomb force is 1.43 N.

5 0

3 years ago

If a force of 450N pushes a box 4 meters in 2 seconds, how much power was developed?

strojnjashka [21]

Work = (force) x (distance) = (450 N) x (4 m) = 1,800 joules

Power = (work) / (time) = (1,800 joules) / (2 sec) = 900 watts .

5 0

3 years ago

An object accelerates to a velocity of 34m/s over a time 13 s the acceleration it experience was 15 m/s2 what was it’s intital v

miv72 [106K]

Vf =Vi + at
Vi =Vf - at
= 34 - 15•13
= - 161 m/s :/

7 0

4 years ago