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emmasim [6.3K]
3 years ago
9

When a car's velocity is positive and its acceleration is negative, what is happening to the car's motion?

Physics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

Assuming rightward is positive, the velocity is positive whenever the car is moving to the right, and the velocity is negative whenever the car is moving to the left. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

Explanation:

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In a crash test, a car with a mass of 1600 kg is initially moving at a speed of 20 m/s just before it collides with a barrier. T
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Answer:

The answer to the given points can be defined as follows:

Explanation:

In point 1:

\bold{v_f^2=  v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\

      =0.9 \ m \\

put the value in the above formula:

\to 0=  20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \  \frac{m}{s^2}

 \bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to  222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}

for point 2:

t= 0.0900 \ s  -\text{found above}

for point 3:

\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\

         =1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N

5 0
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What voltage would be measured across the 15 ohm resistor?
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Answer: That depends on what other components are in the same circuit

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If there's nothing else, and the battery is connected across the 15-ohm

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10 volts.

Explanation:

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= 27.777

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3 years ago
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