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mariarad [96]
3 years ago
14

A race car decelerating by 3 m /s to 10 m / s has an acceleration of 25

Physics
1 answer:
Scilla [17]3 years ago
7 0

Answer:

then it will stop

Explanation:

You might be interested in
Blocks A (mass 3.50 kg) and B (mass 6.50 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
Vedmedyk [2.9K]

Answer:

(a) V (A) =  0.7 m/s,

(b) V (A) =  0.7 m/s,

(c) V (B) =  0.7 m/s

(d) u= - 0.60 m/s

(e) v = 0.75 m/s

Explanation:

Given:

M(A) =3.50 Kg, M(B)=6.50 Kg, V(A) = 2.00 m/s, V(B) = 0 m/s

Sol:

a)  law of conservation of momentum

M(a) x V(A) + M(B) x V(B) = ( M(a) + M(B) ) V      (let V is Common Velocity of Both block)

so 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s = (3.50 Kg + 6.50 Kg ) V

after solving V =  0.7 m/s

After the collision the velocities of the both block will be as the the spring is compressed maximum.

V (A) =  0.7 m/s

b)  V(A) =  0.7 m/s ( Part (a) and Part (a) are repeated )

c) as stated above the in the Part (a)

V(B) =  0.7 m/s

d) When the both blocks moved apart after the collision:

Let u=velocity of block A after the collision.

and v = velocity of block B after the collision.

then conservation of momentum

M(a) x V(A) + M(B) x V(B) = M(a) x v + M(B) x u

⇒ 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s =  3.50 Kg x u + 6.50 Kg x v

⇒ 2.00 m/s = u + 1.86 v -----eqn (1)  ( dividing both side by 3.50 Kg)

For elastic collision  

the velocity relative approach = velocity relative separation

so 2.00 m/s = v-u  ----- eqn (2)

⇒v = u + 2.00 m/s

putting this value in eqn (1) we get

2.00 m/s = u + 1.86 (v + 2.00 m/s)

u= - 0.60 m/s

e) putting v= 2.00 m/s in eqn (1)

2.00 m/s = - 2.32 m/s + 1.86 v

v = 0.75 m/s

5 0
3 years ago
Technician A says that LCDs may be slow to work at low temperatures. Technician B says that an LCD dash display can be damaged i
never [62]

Answer:

c

Explanation:

6 0
3 years ago
Two boxes of masses m=35kg and m2=45kg, are hung vertically from opposite ends of a rope passing over a rigid horizontal metal r
Over [174]

Answer:

a) 5.51m/s² b) 192.94N c) 1.38m each

Explanation:

Given two boxes of masses m1 = 35kg and m2 = 45kg hung vertically from opposite ends of a rope passing over a rigid horizontal metal rod, we will analyze the forces acting on each body.

According Newton's second law, Force = mass ×acceleration

The forces acting on body of mass m1 are the tension (T) and the frictional force (Ff) which opposes the tension.

Taking the sum of horizontal forces acting on mass m1, we will have;

T +(-Ff) = m1a

T - Ff = m1a... (1)

For the mass m2, the forces acting on the body are in the vertical direction and this forces are the weight (W) acting downwards and the tension(T) acting upwards. The sum of the forces in the body is given as ;

W + (-T) = m2a

W-T = m2a ...(2)

Since W = mg, equation 2 will become;

m2g - T = m2a...(2)

Solving equation 1 and 2 simultaneously to get the tension and the acceleration, we have;

T - Ff = m1a ... 1

m2g - T = m2a ... 2

Since friction is negligible, Ff = 0

Adding the two equation will give;

m2g-Ff = m2a+m1a

Since Ff =0

m2g = (m2+m1)a

a = m2g/m1+m2

a = 45(9.8)/45+35

a =441/80

a = 5.51m/s²

b) Substituting a = 5.51 into equation 1 to get the tension T in the rope will give;

T = m1a

T = 35×5.51

T = 192.94N

c) since velocity = displacement/time

Displacement = velocity × time

To get the velocity, since acceleration = velocity/time,

Velocity = acceleration ×time

Velocity = 5.51× 0.5

Velocity = 2.76m/s

Displacement of each box will be the same since they are moving with the same acceleration.

Displacement = 2.76m/s × 0.5s

Displacement of each boxes = 1.38m

7 0
3 years ago
Suggest how this affects friction
Reil [10]

You have to measure.

Explanation:

7 0
3 years ago
What happens to the inertia of an object of its mass is decreased?
Verizon [17]
 <span>The inertia of an object increases if the mass is decreased. Inertia is the resistance of any physical object to a change in its state of motion or rest. It is represented numerically by an object's mass.</span>

3 0
3 years ago
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