An unknown element X has the following isotopes: 126X (22.00%
1 answer:
Answer:
Explanation:
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In this case, since the average atomic mass of an element, when given the atomic mass and the percent abundance of the naturally occurring isotopes is computed as shown below for this unknown element:
Whereas the atomic mass of each isotope is multiplied by the percent abundancy; we obtain:
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Answer:
0.37atm
Explanation:
Given parameters:
Initial pressure = 0.25atm
Initial temperature = 0°C = 273K
Final temperature = 125°C = 125 + 273 = 398K
Unknown:
Final pressure = ?
Solution:
To solve this problem, we use a derivative of the combined gas law;
=
P and T are pressure and temperature
1 and 2 are initial and final values
=
P2 = 0.37atm
Answer:
Substance is Aluminium
Explanation:
We are given;
Mass; m = 13.5 grams
Volume; V = 5 cm³
Formula for density is;
density = m/V
Density = 13.5/5
Density = 2.7 g/cm³
From the table attached, we can see that the element with a corresponding density of 2.7 is Aluminium
