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andriy [413]
2 years ago
15

You place a box weighing 268.3 N on an inclined plane that makes a 42◦ angle with the horizontal.

Physics
1 answer:
vivado [14]2 years ago
5 0

Answer:

Wy = - 268.3*cos(42) = - 199.38 [N]

Wx = 268.3*sin(42) = 179.52 [N]

Explanation:

To solve this problem we must make a free body diagram, in the attached image we can see a free body diagram.

Taking the inclined X & y axes with the same angle of 42°, we can see that the weight can be decomposed on both axes.

Since the angle is adjacent to the y-axis, we can use the cosine function

Wy = - 268.3*cos(42) = - 199.38 [N]

Wx = 268.3*sin(42) = 179.52 [N]

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A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between
Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

Initial speed = 5.49 m/s

Coefficient of kinetic friction = 0.229

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We need to calculate the acceleration of sled

Using formula of acceleration

a = \dfrac{F}{m}

Where, F = frictional force

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a=\dfrac{\mu mg}{m}

a=\mu g

a=0.229\times9.8

a=2.244\ m/s^2

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Using equation of motion

v^2=u^2-2as

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Put the value in the equation

v ^2=(5.49)^2-2\times2.244\times3.89

v=\sqrt{(5.49)^2-2\times2.244\times3.89}

v=3.56\ m/s

Hence, The speed of the sled is 3.56 m/s.

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3 years ago
I need help with this
lord [1]

Answer:

0.832

Explanation:

8.320 x 10 to the negative 1st power is 0.832

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