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Brums [2.3K]
3 years ago
12

A box is placed on a table. If an upward pulling force on the box is slightly less than the weight of the box, what will happen

to the box?
A) It will remain on the table.
B) It will start to fall through the table.
C) It will move upward briefly and then move downward.
D) It will start to rise off the table and continue speeding up.
Physics
1 answer:
aniked [119]3 years ago
5 0

Answer:

<u><em>A for certain.</em></u>

Explanation:

I got it right on the test, thanks to the other brainly answerer teresecaway. But knowing the answer doesnt help much if you dont know WHY. The reason WHY is as follows. At first you might think it would be B, because the downwards force is greater than the upwards force. I thought that maybe upwards force would also count as the table supporting it, but no, thats just structural inanimate solid table. The answer is A. gravity would have to be HIGHLY raised or somebody pressing down on it, to make it fall through the table.

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A basketball player has made 60​% of his foul shots during the season. Assuming the shots are​ independent, find the probability
marissa [1.9K]

Answer:

a) 0.0864

b) 0.0384

c) 0.936

Explanation:

Probability that he makes his shot, P(A) = 0.6

Probability that he doesn't make the shot, P(A') = 1 - P(A) = 1 - 0.6 = 0.4

a) Probability that he Misses for the first time on his fourth attempt

P(A) × P(A) × P(A) × P(A') = 0.6 × 0.6 × 0.6 × 0.4 = 0.0864

b) Probability that he Makes his first basket on his fourth shot

P(A') × P(A') × P(A') × P(A) = 0.4 × 0.4 × 0.4 × 0.6 = 0.0384

c) Probability that he Makes his first basket on one of his first 3 shots

Sum of the probabilities that he makes all three first shots, two of the first three shots and one of the first three shots with the order irrelevant.

- Probability that he makes all first three shots = P(A) × P(A) × P(A) = 0.6 × 0.6 × 0.6 = 0.216

- Probability that he makes two out of the first three shots = (P(A) × P(A) × P(A')) + (P(A) × P(A') × P(A)) + (P(A') × P(A) × P(A)) = 3(0.6 × 0.6 × 0.4) = 0.432 (it's multipled by 3 because the probability is the same regardless of order)

- Probability of making only one of the first three shots = (P(A) × P(A') × P(A')) + (P(A') × P(A) × P(A')) + (P(A') × P(A') × P(A)) = 3(0.6 × 0.4 × 0.4) = 0.288 (It's multiplied by 3 too because the probabilities are the same too, regardless of order).

Probability that he Makes his first basket on one of his first 3 shots = 0.216 + 0.432 + 0.288 = 0.936

5 0
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3 0
4 years ago
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lianna [129]

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<u>Given the following data:</u>

  • Angle of inclination = 30.0°.

<h3>What is a free-body diagram?</h3>

In Science, a free-body diagram can be defined as a graphical illustration which is typically used to visualize moments, tension, and applied forces that are acting on an isolated or rigid body (object) while using arrows pointing in the direction of these forces.

In this scenario, the weight of the ant is the force that acts on the anthill in the <u>downward direction</u> and at angle of 30° rom the vertical.

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8 0
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Answer:

Before start of slide velocity will be 14.81 m/sec

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v^2=219.52

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3 0
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son4ous [18]
That's a 'direct' or 'proportional' variation.

The variables are related by the equation      Y = K X .

That constant ratio is the number    ' K ' .

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