Answer:
electrical energy change into heat and light energy.
Answer:
<h3>1/16</h3>
Explanation:
According to the coulombs law, the force existing vetween the ions is expressed as;
F = kQq/r² .... 1
Q and q are the ions
r is the distance between the ions
If the distance between the ion is quadrupled, then;
F2 = kQq/(4r)²
F2 = kQq/16r² ... 2
Divide equation 2 by 1;
F2/F = kQq/16r² ÷ kQq/r²
F2/F = kQq/16r² × r²/kQq
F2/F = 1/16
F2 = 1/16 F
Therefore the coulombic force between two ions is reduced to<u> 1/16 </u>of its original strength when the distance between them is quadrupled.
The strength of electric field E is 17 N / C.
<u />
<u>Explanation:</u>
Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by
E = F / q
where E represents the electric field strength,
F represents the force in newton,
q represents the charge in coulomb.
Given the charge q = 0.30 coulombs
force F = 5.0 N
Electric field strength E = force / charge
= 5.0 / 0.30
E = 16.66 = 17 N / C.
Answer:
The voltage will quadruple
Explanation:
The power dissipated in a circuit is given by
where
V is the voltage
R is the resistance
In this problem, the voltage across the circuit is doubled:
V' = 2V
So the new power dissipated is
so, the power dissipated will quadruple.
<u>False, </u>
<u>True,</u>
A build up of positive charge builds up on the ground under the cloud, attracted to the negative charge in the cloud. The earth's positive charge concentrates to anything that sticks up - trees, lightning conductors,
<u>100</u>