Mass of car, M=2000kg
Velocity, V=72× 5/18 =20ms¹
Apply kinematic equation of motion
v² -u² = as
0 − 20² =2a×20
a=−10ms^-2
Breaking force, F=ma=2000×10=20 kN
Apply first kinematic equation
v = u +at
A truck of mass 8000 kg is moving with a velocity of 50 km/h and collides with a bus of mass 5000 kg coming from opposite direct
1 answer:
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Answer:
Total moment of inertia when arms are extended: 1.613
Explanation:
This second part of the problem could be a pretty complex one, but if they expect you to do a simple calculation, which is what I imagine, the idea is just adding another moment of inertia to the first one due to the arms extended laterally and use the moment of inertia for such as depicted in the image I am attaching.
In that image:
L is the length from one end to the other of the extended arms (each 0.75m from the center of the body) which gives 1.5 meters.
m is the mass of both arms. That is: twice 5% of the mass of the person: which mathematically can be written as: 2 * 0.05 * 56.5 = 5.65 kg
Therefore this moment of inertia to be added can be obtained using the formula shown in the image:
Now, one needs to add this to the previous moment that you calculated, resulting in:
0.554 + 1.059 = 1.613
The exhaust temperature is 200 K
Explanation:
The maximum efficiency of a machine is given by the equation:
where:
is the temperature of the hot reservoir
is the temperature of the cold reservoir
For the engine in this problem, we have:
(efficiency is 33.3%)
is the temperature of the hot reservoir
Re-arranging the equation for , we can find the exhaust temperature (the temperature of the cold reservoir):
Learn more about temperature:
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