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hodyreva [135]
2 years ago
10

The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is

greater or smaller or the same as the force with which the moon attracts the earth? Why?
Physics
1 answer:
KengaRu [80]2 years ago
5 0

Answer:

Gravitational attraction is caused by the mass of an object. Since Earth is far more massive than the Moon, the gravitational force exerted on the Moon is far greater than that of the Moon on the Earth. An example of the difference: while the Moon causes tides on the Earth, the Earth has the Moon locked so that the same face (minus some wobbling) is always visible from the Earth

Explanation:

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earnstyle [38]

Sound waves travel faster through <em>solids</em> than they do through gases or liquids.  <em>(C)  </em>They don't travel through vacuum at all.

Example:

Speed of sound in normal air . . . around 340 m/s

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3 0
3 years ago
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If temperature increases, then pressure __________.
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6 0
3 years ago
A wire loop of radius 0.50 m lies so that an external magnetic field of magnitude 0.40 T is perpendicular to the loop. The field
vazorg [7]

The magnitude of the induced emf is given by:

ℰ = |Δφ/Δt|

ℰ = emf, Δφ = change in magnetic flux, Δt = elapsed time

The magnetic field is perpendicular to the loop, so the magnetic flux φ is given by:

φ = BA

B = magnetic field strength, A = loop area

The area of the loop A is given by:

A = πr²

r = loop radius

Make a substitution:

φ = B2πr²

Since the strength of the magnetic field is changing while the radius of the loop isn't changing, the change in magnetic flux Δφ is given by:

Δφ = ΔB2πr²

ΔB = change in magnetic field strength

Make another substitution:

ℰ = |ΔB2πr²/Δt|

Given values:

ΔB = 0.20T - 0.40T = -0.20T, r = 0.50m, Δt = 2.5s

Plug in and solve for ℰ:

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3 0
3 years ago
Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni
joja [24]

Answer:

Explanation:

Use the following equation:

E=\frac{q}{F} and solve for F:

F=\frac{q}{E} and filling in:

F=\frac{.0600}{1500}

F = 4.0 × 10^{-4 N

3 0
2 years ago
A golf ball reaches a height of 150 m before it stops rising and starts to fall to the ground. What is the golf balls speed (rou
artcher [175]

Answer:

v = 54 m/s

Explanation:

Given,

The maximum height of the flight of golf ball, h = 150 m

The velocity at height h, u = 0

The velocity of the golf ball right before it hits the ground, v = ?

Using the III equations of motion

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Substituting the given values in the above equation,

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4 0
3 years ago
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