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3 years ago

In today's experiment, Solutions A and B are prepared as follows.

Chemistry

1 answer:

hram777 [196]3 years ago

3 0

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

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Which of the following situations best shows deposition?

KATRIN_1 [288]

Answer:

chemistry, deposition occurs when molecules settle out of a solution. Deposition can be viewed as a reverse process to dissolution or particle re-entrainment. It is a phase change from the gaseous state to a solid, without passing through the liquid state, also called re-sublimation.

Explanation:

Examples include beaches, deltas, glacial moraines, sand dunes and salt domes. In severely cold temperatures frost will form on windows because the water vapor in the air comes into contact with a window and immediately forms ice without ever forming liquid water.

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3 years ago

What is the mass of oxygen in 25.0 grams of potassium permanganate , KMnO4?

Katen [24]

Answer:

10.76 grams

Explanation:

Given that the amount of $KMnO_4$ is 25.0 grams.

Mass of 1 mole of $KMnO_4$ = 158 grams

The number of atoms in 1 mole of $KMnO_4$ is 4.

Mass of oxygen in 1 mole of $KMnO_4$ = 16\times 4 = 68 grams.

Here, 158 grams of $KMnO_4$ has 68 grams of oxygen

So, the amount of oxygen in 1 gram of $KMnO_4$ = 68/158 grams

Therefore, the amount of oxygen in 1 gram of $KMnO_4$ = $\frac {68}{158}\times 25$ grams

=10.76 grams

Hence, 25 grams of $KMnO_4$ has 10.76 grams of oxygen.

3 0

3 years ago

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Please help my teacher has like given up

NikAS [45]

Answer:

24.47 L

Explanation:

Using the general gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = 0.0821 Latm/molK

T = temperature (K)

According to the provided information in this question,

P = 1.0 atm

V = ?

n = 1 mol

T = 25°C = 25 + 273 = 298K

Using PV = nRT

V = nRT ÷ P

V = 1 × 0.0821 × 298 ÷ 1

V = 24.465 ÷ 1

V = 24.465

V = 24.47 L

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3 years ago

By the way...... what do those symbols for the elements have in common (for number 7-11): Pb, Au, Cu, Hg, Na ? *

Keith_Richards [23]

Answer:

those have symbols for their Latin or Greek name

Explanation:

hope it helps

8 0

3 years ago

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The combustion of 1.685 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.16 K. The he

AfilCa [17]

Answer:

ΔH = - 2020.57 kJ/mol

Explanation:

Given that :

mass of propanol = 1.685 g

the molar molar mass = 60 g/mol

Thus; the number of moles = mass/molar mass

= 1.685 g/60 g/mol

= 0.028 g/mol

However ;

ΔH = heat capacity C × Δ T

Given that:

The temperature increases from 298.00 K to 302.16 K.

Then ;

Δ T = 302.16 K - 298.00 K

Δ T = 4.16 K

heat capacity C = 13.60 kJ/K

∴

ΔH = 13.60 kJ/K × 4.16 K

ΔH = 56.576 kJ

The equation of the given reaction can be represented as :

$C_3H_7OH_{(l)}+\dfrac{3}{2}O_{2(g)} \to 3CO_{2(g)} +4H_2O_{(l)}$

Thus for 0.028 mol of heat liberated; ΔH = 56.576 kJ

For 1 mole of heat liberated now:

ΔH = 56.576 kJ/0.028 mol

ΔH = 2020.57 kJ/mol

SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;

ΔH = - 2020.57 kJ/mol

5 0

3 years ago

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