Answer:
Explanation:
Given two objects are dropped simultaneously
Object A is 10 m higher than object B therefore
Distance covered by object A is given by
is given by
where y=displacement
u=initial velocity
a=acceleration
t=time
for object B
Subtract 1 and 2 we get
i.e. they will travel equal distance in equal time and distance between them remain 10 m until object B hits the ground
Answer:
1 put the black can in the temperature thing.
2.put the silver can well put water in it and leave it out side for a while.
3.Then you can be the judge of witch one will have a larger increase.
hope this helps :)
happy to help any time:)
Explanation:
Answer:
s = 3 m
Explanation:
Let t be the time the accelerating car starts.
Let's assume the vehicles are point masses so that "passing" takes no time.
the position of the constant velocity and accelerating vehicles are
s = vt = 40(t + 2) cm
s = ½at² = ½(20)(t)² cm
they pass when their distance is the same
½(20)(t)² = 40(t + 2)
10t² = 40t + 80
0 = 10t² - 40t - 80
0 = t² - 4t - 8
t = (4±√(4² - 4(1)(-8))) / 2(1)
t = (4± 6.928) / 2 ignore the negative time as it has not occurred yet.
t = 5.464 s
s = 40(5.464 + 2) = 298.564 cm
300 cm when rounded to the single significant digit of the question numerals.
Answer:
There are many examples of electrostatic phenomena, from those as simple as the attraction of the plastic wrap to one's hand after it is removed from a package to the apparently spontaneous explosion of grain silos, the damage of electronic components during manufacturing, and photocopier & laser printer operation
