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3 years ago

What is Newton's third law motion answer part a and b

Physics

2 answers:

Olenka [21]3 years ago

3 0

Answer:

hope it helps

Explanation:

Newtons third law is that objects exert equal and opposite forces on each other.

'every action has an equal and opposite reaction'.

Ipatiy [6.2K]3 years ago

3 0

Answer:

to every action there's equal and opposite reaction

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Which two forces exist between the protons in an atom

r-ruslan [8.4K]

Answer: The Forces Between Protons at Nuclear Distances. Two protons are subject to two forces; the nuclear force and the electrostatic force. When they are very close together the nuclear force is dominant and when they are far apart it is the electrostatic force which is dominant.

Did that help?

8 0

3 years ago

Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3

lisov135 [29]

Answer: $0.1066\ psi, 15.611\ kN$

Explanation:

Given

the height of the tank is $h=10\ cm$

The diameter of the tank is $d=520\ cm$

Density of solution $\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3$

$(a)$ Water pressure at the bottom of the tank is

$P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa$

$1\ Pa=0.000145038\ psi$

$\Rightarrow P=735\ Pa\ or\ 0.1066\ psi$

$(b) \text{Average force on the bottom is the product of pressure and area of the base}$

$F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN$

6 0

3 years ago

A charge of +1.4×10^6 coulombs moves from point a to b. What is the potential difference between the two points if the work done

Rama09 [41]

The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.

8 0

3 years ago

7. Two workers must pick up bricks that lie on the ground and place them on a worktable. They each

sdas [7]

Answer:

Same work is done by the two workers

The first worker exerts more power than the second person

Explanation:

Work is the product of force and distance moved in the direction of the applied force

Power is the rate at which work is done

7 0

4 years ago

A flywheel with a radius of 0.200m starts from rest and accelerates with a constant angular acceleration of 0.900rad/s2.

kobusy [5.1K]

Answer:

The magnitude of the radial acceleration is 0.754 rad/s²

Explanation:

Given;

radius of the flywheel, r = 0.2 m

initial angular velocity of the flywheel, $\omega_i = 0$

angular acceleration of the flywheel, a = 0.900 rad/s².

angular distance, θ = 120⁰

the angular distance in radian = $\frac{120}{180} \pi = \frac{2 \pi}{3} \ rad$

Apply the following kinematic equation to determine the final angular velocity;

$\omega _f^2 = \omega _i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 + 2(0.9)(\frac{2\pi}{3} )\\\\\omega _f^2 = 3.7699\\\\\omega _f = \sqrt{ 3.7699} \\\\ \omega _f = 1.942 \ rad/s$

The magnitude of the radial acceleration is calculated as;

$\alpha _r = \omega ^2r\\\\\alpha _r = (1.942)^2 (0.2)\\\\\alpha _r =0.754 \ rad/s^2$

Therefore, the magnitude of the radial acceleration is 0.754 rad/s²

4 0

3 years ago