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kirill [66]
3 years ago
9

A car starts from rest and travels for 7.0 seconds with auniform

Physics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer

given,

initial speed = 0 m/s

acceleration of  +2.5 m/s^2 for time 7 s.

final velocity after 7 s

using equation of motion

v = u + a t

v = 0 + 2.5 x 7

v = 17.5 m/s

after 7 sec

Brake is applied, uniform acceleration = -3.0 m/s^2

time = 2 s

speed of the car after 2 s

initial velocity = 17.5 m/s

Again using equation of motion

v = u + a t

v = 17.5 - 3  x 2

v = 11.5 m/s

distance  the car has traveled when brake is applied

v² = u² + 2 a s

11.5² =17.5² - 2 x 3 x s

6 s = 174

s = 29 m

car has moved 29 m after application of the brake.

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A plastic rod that has been charged to − 15 nC touches a metal sphere. Afterward, the rod's charge is − 5.0 nC.
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Answer:

B) electrons transferred from sphere to rod.

(2) 1.248 x 10¹¹ electrons were transferred

Explanation:

Given;

initial charge on the plastic rod, q₁ = 15nC

final charge on the plastic rod, q₂ = - 5nC

let the charge acquired by the plastic rod = q

q + 15nC = -5nC

q = -5nC - 15nC

q = -20 nC

Thus, the plastic rod acquired excess negative charge from the metal sphere.

Hence, electrons transferred from sphere to rod

B) electrons transferred from sphere to rod.

2) How many charged particles were transferred?

1.602 x 10⁻¹⁹ C = 1 electron

20 x 10⁻⁹ C = ?

= 1.248 x 10¹¹ electrons

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7 0
3 years ago
If you place one staple on an electronic balance, the balance still reads 0.0 grams. However, if you place
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4 0
3 years ago
Read 2 more answers
Which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion?
11111nata11111 [884]

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3 years ago
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A boy drags a suitcase along the ground with a force of 100 N. If the frictional force opposing the motion of the suitcase is 50
stira [4]
Fortunately, 'force' is a vector.  So if you know the strength and direction
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When we talk in vectors, one newton forward is the negative of
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the complete solution of the problem.


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That's it.
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