Answer:
Mass of the pull is 77 kg
Explanation:
Here we have for
Since the rope moves along with pulley, we have
For the first block we have
T₁ - m₁g = -m₁a = -m₁g/4
T₁ = 3/4(m₁g) = 323.4 N
Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have
T₂ - m₂g = m₂a = m₂g/4
T₂ = 5/4(m₂g) = 134.75 N
T₂r - T₁r = I·∝ = 0.5·M·r²(-α/r)
∴
Mass of the pull = 77 kg.
Answer:
<em>The change of momentum of the dart is 0.84 Nw.s</em>
Explanation:
<u>Impulse and change of momentum</u>
The change in momentum of an object is its mass times the change in its velocity:
The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:
The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:
The change of momentum of the dart is 0.84 Nw.s
Hi there!
We know that:
U = Potential Energy (J)
K = Kinetic Energy (J)
E = Total Energy (J)
At 10m, the total amount of energy is equivalent to:
U + K = 50 + 50 = 100 J
To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:
100J = mgh
We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².
50J = 10(10)m
m = 1/2 kg
Now, solve for height given that E = 100 J:
100J = 1/2(10)h
100J = 5h
<u>h = 20 meters</u>