Answer
given,
Hunk Finn speed,v_y= 0.7 m/s
Speed of river,v_x = 1.50 m/s
Assuming the speed of the river is in x-direction.
Speed of Hunk Finn to be in y-direction.
Hunk velocity relative to river =
Speed of Hunk relative to river = 1.66 m/s
direction of the boat
Hence, angle of the raft is 24.01°
After my ythorough researching, the orbital velocity of the Earth compare to the Mercury is relative to each other. In addition, Mercury orbits the Sun and it is within the Earth's orbit as its lesser or inferior. The correct answer to the following given statement above is relative to each other.
Answer:
mass of the composite lump is 10 kg
Explanation:
given data
mass = 4 kg
to find out
mass of composite lump
solution
we know energy is conserved so
so m1 = m2 = m0 that is 4kg
and
E(1) release+ E(2) release = E(1,2) rest
so γ(1)m(1)c² + γ(2)m(2)c² = Mc² ..........................1
that why here
|v(1)| = |v(2)| = 3/5 c ......................2
and
γ = 1 / √(1 − v²/c²) .......................3
put here v = 3 and c is 5
γ = 1 /√(1 − 9/25)
γ = 5/4
so
γ(1) = γ(2) = γ = 5/4
so from equation 1
γ(1)m(1)c² + γ(2)m(2)c² = Mc²
M = 2γm0
M = 2(5/4 )(4)
M = 10 kg
so mass of the composite lump is 10 kg
Answer:
The uncertainty in momentum is 5.25x 10^25Jsm
Explanation:
We know that
h bar = h/2π
So
1.05x 10^34=h/2pπ
h=1.05x 10^ 34(2π)=6.597x 10^-34Js
dp=(6.597x10^-34/4pπ)/(1x10^-10)
=5.25x10^-25 Jsm
This is a normal distribution and we can use the standard score to compute for probabilities. We compute the standard score of the given.
z = (x - mu)/sd
z = (2625 - 2600)/50 = 25/50 = 0.5.
Consulting the z-table, P(z <= 0.5) = 0.6915.
P(z > 0.5) = 1 - P(z <= 0.5) = 1 - 0.6915 = 0.3085.
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