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3 years ago

Factors that affect acceleration due to gravity.

Physics

2 answers:

hram777 [196]3 years ago

8 0

Answer

Factors Affecting Acceleration Due to Gravity

(1) Position on the planetary surface, it is higher at the axis (poles),

(2) Mass of the planet, higher with planets of larger masses

(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.

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Kamila [148]3 years ago

5 0

Explanation:

the factors affecting acceleratiom due to gravity are:

Altitude above the earth’s surface.

Depth below the earth’s surface.

The shape of the earth.

Rotational motion of the earth.

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What two factors determine the density of a fluid?

tekilochka [14]

Answer:

Mass and volume.

Explanation:

The equation for density is always mass divided by volume. To determine the density of a fluid, you would need to find its volume and its mass.

6 0

4 years ago

Someone throws their laptop with a horizontal component of velocity of 25 m/s. It takes the laptop 3.00 seconds to come back to

prisoha [69]

1) The horizontal range of the laptop is 75.0 m

2) The initial vertical component of the velocity is 14.7 m/s

Explanation:

The motion of the laptopin this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

To find the horizontal range of the laptop, we just need to analyze its horizontal motion.

We know that:

- The laptop moves horizontally with a constant velocity of $v_x = 25 m/s$

- The time of flight of the laptop is $t=3.00 s$

So, the horizontal range of the laptop is given by

$d=v_x t = (25)(3.00)=75.0 m$

The total time of flight of a projectile is given by

$t=\frac{2u_y}{g}$

where

$u_y$ is the initial vertical component of hte velocity

$g=9.8 m/s^2$ is the acceleration of gravity

Here we know that the time of flight is

$t=3.00 s$

Therefore, we can solve the formula for $u_y$ , to find the initial vertical velocity:

$u_y = \frac{tg}{2}=\frac{(3.00)(9.8)}{2}=14.7 m/s$

Learn more about projectile motion:

brainly.com/question/8751410

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3 0

3 years ago

A 20 kg child is on a swing that hangs from 3.0-m-long chains. what is her maximum speed if she swings out to a 45° angle?

fomenos

The solution for this problem is:

Remember that this doesn’t depend on the mass of the child.

E = T + U = constant
E (maximum height) = T + U =U = mgh = mg[r - r· cos (Θ)]

E (bottom height) = T + U = T = ½mv² = mg[r - r · cos (Θ)]

v² = 2g[r – r · cos (Θ)]

v = √ (2g[r-r·cos(Θ)])

= √(2(9.8)[3 – 3 · cos (45°)])

= 4.15 m/s or 15 kph

4 0

4 years ago

Read 2 more answers

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ELEN [110]

Answer:

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8 0

3 years ago

William tell must split the apple atop his son's head from a distance of 24 m. when he aims directly at the apple, the arrow is

mezya [45]

Let x = the angle of elevation for shooting the arrow.

Assume
g = 9.8 m/s²
No wind resistance
The vertical launch velocity is 25.1 sin(x) m/s
The horizontal velocity is 25.1 cos(x) m/s

The time of flight is
24/[25.1 cos(x)] s = 0.9562 sec(x) s

Therefore
0.5*[0.9562 sec(x)]*(9.8) = 25.1 sin(x)
4.6854 = 25.1* sin(x)cos(x)
sin(2x) = 0.3733
2x = sin⁻¹ 0.3733 = 21.92 deg
x = 10.96 deg

Answer: 11 degrees (nearest integer)

8 0

4 years ago

Read 2 more answers

Factors that affect acceleration due to gravity.​

Factors that affect acceleration due to gravity.